Graph the image of square CDEF after a dilation with a scale factor of 2, centered at the
1 answer:
You might be interested in
Let 
the price of a ticket
Let
the cost to put on the show
Formula:
(profit) = (ticket price) * (number of people) - (cost to put on show)
We have two equations here:
Solve:
⇒
⇒
⇒
⇒
So the price of a ticket is $5, and the cost to put on the show is $100.
Let
Formula:
(profit) = (ticket price) * (number of people) - (cost to put on show)
We have two equations here:
Solve:
⇒
⇒
⇒
⇒
So the price of a ticket is $5, and the cost to put on the show is $100.
Answer:
a) see the plots below
b) f(x) is exponential; g(x) is linear (see below for explanation)
c) the function values are never equal
Step-by-step explanation:
a) a graph of the two function values is attached
__
b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).
__
c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.
In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.
The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:
Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:
We can calculate the equation of p by using its slope and its point P:
Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:
We can calculate the equation of p by using its slope and its point P: