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Mazyrski [523]
3 years ago
5

Can someone help me on this last question

Mathematics
1 answer:
NISA [10]3 years ago
4 0

Yes I can. The answer is most likely B. I am 99.9% sure this is the correct awnswer

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A company fills a warehouse will two types of goods A and B . they both come in tall boxes which cannot be stocked. one box of A
inessss [21]

Answer:

(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20

(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20

Step-by-step explanation:

There are two inequalities in mind, the first of the surface and the second of the price. Always bearing in mind that the minimum are 50 of A and 20 of B.

The first

A occupies 1/2 m and B occupies 1/2 m of surface, and the limit is 100 m of surface. Thus:

(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20

The second:

A costs 5,000 and B costs 30,000, and the limit is 1,500,000. Therefore:

(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20

5 0
3 years ago
Can anyone help me out
Genrish500 [490]

Answer:

12k^5 +24k⁴+30k³

Step-by-step explanation:

the area = 6k³(2k²+4k+5)

= 12k^5 +24k⁴+30k³

5 0
3 years ago
The price, P, of a certain stock is given by the formula P = -6t + 50 when t is the number of years since 2000. Find the price o
oksian1 [2.3K]

Answer:

year 2000: P = 50

year 2004: P = 24

Step-by-step explanation:

t is the number of years since 2000, so for the year 2000, we have that t = 0.

Using this value in the equation, we find that:

P = -6 * 0 + 50 = 50

The price of the stock in year 2000 is 50.

For the year 2004, we have that t = 4, so using this value in the equation for P, we have:

P = -6 * 4 + 50 = -24 + 50 = 26

The price of the stock in year 2004 is 24.

3 0
3 years ago
Please help me with question 3 guys
777dan777 [17]
Equiangular. They are all 90 degrees but they don’t have the same length of sides so they are equiangular meaning equal angles.
8 0
2 years ago
How many times would you expect to role a 2 on a 6 sided die in 50 trials
Keith_Richards [23]
The six sided die has 6 sides (with numbers 1,2,3,4,5 and 6).  That's why the probability to roll number 2 in one trial is equal to \frac{1}{6}.If you'll dol  50 trials, then you can expect \frac{50}{6}=  \frac{25}{3} times to roll number 2 (8 or 9 times).

3 0
3 years ago
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