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3 years ago

11

Help I’ve tried many times , answer ended up wrong .

1 answer:

Nataly [62]3 years ago

4 0

Step-by-step explanation:

${15}^{2} = {12}^{2} + {x }^{2} \\ 255 - 144 = {x}^{2} \\ 81 = {x}^{2} \\ \sqrt{81 } = x \\ 9 = x$

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Aaron has a digital scale. He puts a marshmallow on The digital scale and it reads 7.2 grams. How much would you except 10 marsh

madreJ [45]

Answer:

72 grams

Step-by-step explanation:

If one marshmallow weighs 7.2 all you have to do is take that times 10, which would give you 72 grams as the answer.

4 0

4 years ago

Need Help ASAP! Thank you!

shtirl [24]

Answer:

b.

Step-by-step explanation:

B because the slope of f(x) is 1 yet the slope of g(x) is 1/3

8 0

3 years ago

An urn contains 4 purple marbles and 3 pink marbles. Two marbles are drawn at random. What is the probability that both marbles

Archy [21]

Answer: 16/49

Step-by-step explanation:

The probability of pulling a purple marble is 4/7, since 4+3 is 7.
Since the marbles are replaced, the probability does not change when pulling out marbles.

To combine probabilities, we multiply them

$\frac{4}{7} * \frac{4}{7} = \frac{16}{49}$

3 0

2 years ago

Read 2 more answers

Daniel [21]

Answer:

$x=\sqrt{\frac{7(4+\sqrt{15})}{2}}$

Step-by-step explanation:

From the way it is written, the $x$ is outside the square root. I will rewrite it as:

$x\sqrt{5} =x\sqrt{3} +\sqrt{7}$

$x\sqrt{5}-x\sqrt{3}=\sqrt{7}$

$x(\sqrt{5} - \sqrt{3} )=\sqrt{7}$

$x= \frac{\sqrt{7} }{\sqrt{5} - \sqrt{3}} \implies \frac{\sqrt{7}(\sqrt{5} + \sqrt{3}) }{2}$

$x=\frac{1}{2} \sqrt{7} (\sqrt{5} + \sqrt{3} )$

$x=\frac{\sqrt{35}}{2} +\frac{ \sqrt{21}}{2}$

$x=\frac{\sqrt{35}+\sqrt{21}}{2}$

Multiply denominator and numerator by 3

$x=\frac{3\sqrt{35}+3 \sqrt{21}}{6}$

Factor $\sqrt{3}$

$\sqrt{3} (\sqrt{105}+3 \sqrt{7})$

$x=\frac{\sqrt{3} (\sqrt{105}+3 \sqrt{7})}{6}$

Divide denominator and numerator by $\sqrt{3}$

$x=\frac{\sqrt{105}+3 \sqrt{7}}{2\sqrt{3} }$

Let's rewrite it again

$x=\frac{\sqrt{ (\sqrt{105}+3 \sqrt{7})^2}}{\sqrt{12} }$

$x=\sqrt{ \frac{1}{12} \cdot (\sqrt{105}+3 \sqrt{7})^2}$

It is already in the form $\sqrt{\frac{a}{b} }$

Expanding the perfect square, we have

$63+42\sqrt{15}+105$

$\frac{63}{12} +\frac{42\sqrt{15}}{12} +\frac{105}{12}$

$\frac{21}{4} +\frac{7\sqrt{15}}{2} +\frac{35}{4}$

Factor $\frac{7}{2}$

$\frac{7}{2} (4+\sqrt{15} )$

Therefore,

$x=\sqrt{\frac{7}{2} \left(4+\sqrt{15} \right)}$

$x=\sqrt{\frac{7(4+\sqrt{15})}{2}}$

7 0

3 years ago

Read 2 more answers

Any one pls helpp! i dont understand this???

ozzi

Answer:

X= 10, 20, 30, 40, 50, 60

Step-by-step explanation:thats

thats all i know

3 0

3 years ago

Read 2 more answers