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lisov135 [29]
3 years ago
6

Each side length of a triangle is 4 cm. What type of figure is it ?

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

Equilateral and acute

Explanation:

Equilateral triangles refer to triangles where all side lengths are equal. Acute triangles are triangles where all angles are acute (less than 90^{\circ}). Since each side length of the triangle is 4cm, the triangle is an equilateral triangle. Due to the property of equilateral triangles where each angle is equivalent to 60^{\circ}, we can conclude that this triangle is equilateral and acute.

Hope this helps :)

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Doss [256]

Answer:

Last option

(AB)^2+(BC)^2=(AC)^2

Step-by-step explanation:

REASON because it follows Pythagoras theorem

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3 years ago
Transversal EF cuts parallel lines AB and CD as shown in the diagram and m4=55.1 what are m5 and m7? . A. m<5=34.9 and m7=145
Shalnov [3]
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Simplify the expression 8−(−2)/7−12
Ymorist [56]

(8−(−2))/7−12

10/-5

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3 years ago
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prisoha [69]
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Determine whether each expression below is always, sometimes, or never equivalent to sin x when 0° < x < 90° ? Can someone
Lubov Fominskaja [6]

Answer:

(a)\ \cos(180 - x) --- Never true

(b)\ \cos(90 -x) --- Always true

(c)\ \cos(x) ---- Sometimes true

(d)\ \cos(2x) ---- Sometimes true

Step-by-step explanation:

Given

\sin(x )

Required

Determine if the following expression is always, sometimes of never true

(a)\ \cos(180 - x)

Expand using cosine rule

\cos(180 - x) = \cos(180)\cos(x) + \sin(180)\sin(x)

\cos(180) = -1\ \ \sin(180) =0

So, we have:

\cos(180 - x) = -1*\cos(x) + 0*\sin(x)

\cos(180 - x) = -\cos(x) + 0

\cos(180 - x) = -\cos(x)

-\cos(x) \ne \sin(x)

Hence: (a) is never true

(b)\ \cos(90 -x)

Expand using cosine rule

\cos(90 -x) = \cos(90)\cos(x) + \sin(90)\sin(x)

\cos(90) = 0\ \ \sin(90) =1

So, we have:

\cos(90 -x) = 0*\cos(x) + 1*\sin(x)

\cos(90 -x) = 0+ \sin(x)

\cos(90 -x) = \sin(x)

Hence: (b) is always true

(c)\ \cos(x)

If

\sin(x) = \cos(x)

Then:

x + x = 90

2x = 90

Divide both sides by 2

x = 45

(c) is only true for x = 45

Hence: (c) is sometimes true

(d)\ \cos(2x)

If

\sin(x) = \cos(2x)

Then:

x + 2x = 90

3x = 90

Divide both sides by 2

x = 30

(d) is only true for x = 30

Hence: (d) is sometimes true

8 0
3 years ago
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