Answer:
1. 1/4 4 1 4 4 16 64 1024
2. 118
Step-by-step explanation:
1. 16 is obtained as 1024/64 = 16
before 16 goes: 64/16 = 4
before 4 goes: 16/4 = 4
before the second 4 goes: 4/4 = 1
before 1 goes: 4/1 = 4
before the third 4 goes: 1/4
2. From row 1 to row k, there are k² numbers (notice that rows finished in 1, 4, 9, etc., all perfect squares). 12² = 144, so 140 is on 12th row.
A number in row k is 2k less than the number directly below it. For example, 3 is on 2nd row, then is 2*2 = 4 units less than the number directly below it, which is 7.
The number above 140 is on the 11th row, then above 140 is 140 - 2*11 = 118.
Answer:
a)
i) we have the equation:
3*x - 2*y
We want to find a common multiple of 3 and 2.
One can be:
3*6 = 18
2*9 = 18
And both numbers 6 and 9 are on the list, then if we take:
x = 6, y = 9
we get:
3*6 - 2*9 = 18 - 18 = 0
The solution is x = 6, y = 9.
ii) The greatest possible value of:
3*x - 2*y
Will be when x is the largest value of the list (because it is on the positive term) and y is the smallest value on the list (because it is on the negative term)
then we need to have x = 10, y = 5
The value will be:
3*10 - 2*5 = 30 - 10 = 20
iii) Now we want to have the smallest value on x, and the largest one on y, then:
x = 5, y = 10
The smallest value of the equation will be:
3*5 - 2*10 = 15 - 20 = -5
B) We want to solve:
5*(a - 4*b)
when:
a = -7
b = 1/4
This is kinda easy, we just need to replace the variables in the equation to get:
5*(a - 4*b) = 5*(-7 - 4*(1/4)) = 5*(-7 - 4/4) = 5*-8 = -40
Y= 2x + 1, hope this helps
Answer:
A(r) = √2 * r
A(r) Domain is R { r ; r > 0}
Step-by-step explanation:
Diagonals of a square intercept each other in a 90° angle. The four triangles resulting from diagonal interception are equal and are isosceles triangles, with hipotenuse a side of the square
Therefore we apply Pythagoras theorem
Let x be side of square, and r radius of the circle, ( diagonals touch the circle) then
x² = r² + r²
x² = 2r²
x = √2 * r
Now Aea of square is :
A = L² where L is square side
A(r) = √2 * r
Domain of A(r) = R { r, r > 0}
Answer:
14+(59*q)
Step-by-step explanation:
