Answer:
See attached image for the drawing of the first four trees (circled in green)
The patterns is:
x = 2+3n and y= 3+2n
Position of 7th tree is: (20,15) (circled in orange in the image)
Step-by-step explanation:
Starting at the location (2,3) the next x and y positions are given by:
x = 2+3n since the horizontal position needs to be increased by 3 units on each iteration,
and y= 3+2n since the vertical position needs to be increased by 2 units on each iteration
being n= 1 through 6 (to account for the next 6 trees that need to be planted)
With such pattern, the location of the seventh tree would be:
x = 2 + 3*6 =2 + 18 = 20
y = 3 + 2*6 = 3 + 12 = 15
That is, the point (20,15) on the plane.
Also see attached image.
<span>Simplifying
17x2 + -12x = 0
Reorder the terms:
-12x + 17x2 = 0
Solving
-12x + 17x2 = 0
Solving for variable 'x'.
Factor out the Greatest Common Factor (GCF), 'x'.
x(-12 + 17x) = 0
</span>
Answer & Step-by-step explanation:
For this problem, we will use the distance formula.
![d=\sqrt{(x2-x1)^2+(y2-y1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D)
For our (x1, y1), we will use (-3, 1). For our (x2, y2), we will use (1, 5). Now let's plug in our numbers and solve the problem.
![d=\sqrt{(1-(-3))^2+(5-1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%281-%28-3%29%29%5E2%2B%285-1%29%5E2%7D)
![d=\sqrt{4^2+4^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B4%5E2%2B4%5E2%7D)
![d=\sqrt{16 + 16}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B16%20%2B%2016%7D)
![d=\sqrt{32}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B32%7D)
![d=5.657](https://tex.z-dn.net/?f=d%3D5.657)
So, the distance between (-3,1) and (1,5) is 5.657 units.
It would be the top right
because they are increasing by intervals of 4 each time. it can’t be the others because top left those are increasing by 5, bottom left decreasing by 4, and bottom right decreasing by .5.