<span>a) It is Win with snowfall OR Win without snowfall = 32% + 41% = 73%
b) It is Snowfall on game day AND Win = 29% * 32% = 9.28%
c) It is 32% * 29% / 73% = 12.71 %</span>
The distance between the ships is 26.65.
<h3>How to illustrate the distance?</h3>
Based on the information given, after 3 hours, the distance of ship B will be:
= 20 + (17 × 3)
= 71.
A = 21 × 3 = 63
Well calculate the square root which will be:
A² + B² = 71² + 63²
= 5041 + 3969
= 9010
Therefore, ✓9010 = 94.92
Finally, the distance will be:
= (63 × 21) + (71 × 17) / 94.92
= (1323 + 1207)/94.92
= 26.65
Learn more about distance on:
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From F.S 1, consider this series : 8, 1, 8, 8, 64, 64*8.
Again, consider the series 2, 1/4, 1/2, 1/8, 1/16, 1/(8*16). Clearly, the difference of the 6th and the 3rd term is different for them. Insufficient.
<span>From F.S 2, let the series be </span><span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span></span><span>. Now we know that </span><span><span>a<span>b2</span>=1</span><span>a<span>b2</span>=1</span></span>. The required difference =<span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span></span><span>= 0.Sufficient.</span>
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(Hope this helps you)
The answer is -18 because 15 + 3 is 18 and that is then turned negative
