Answer:
T = .17m + 50
Step-by-step explanation:
T = Total cost
M = Mile
Answer:
1×3 or 3×3 I think...........
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Answer:
arc DB length = 14π feet
Step-by-step explanation:
Assuming point A is the center of the circle, arc DC has measure 180°. Arc DB has measure 40° less, so is 140°. Since you want this in terms of π, we need to convert the degree measure to radians. We do that by multiplying by (π/180) radians per degree:
arc DB = 140° = 140°(π/180°) radians
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Now that we know the arc measure in radians, we can find the length of the arc. It is given by the formula ...
s = rθ
where r represents the radius and θ is the measure of the arc in radians.
The arc length is ...
s = (18 ft)(7π/9) = 14π ft
Arc DB has a length of 14π feet.
Answer:
Step-by-step explanation:
The anwser is 2,3,4,5
