Answer:
(-1, 5)
Step-by-step explanation:
Rearrange the the first equation to have y on one side and all other values on the other side
y = 1 - 4x
since both of the equations are equal to y, set them equal to each other an solve for x.
1 - 4 x = x + 6
-5 = 5 x
x = -1
plug this back into the second equation to get y = 5
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
4.09, 4 2/3 (4.66), 4.7, 21/4 (5 1/4, 5.25)
The two friends will be 150 miles apart, when the sum of the distances covered by the them is 150 miles.
distance = speed x time.
Let the time covered when they are 150 miles apart be x, then:
40x + 35x = 150
75x = 150
x = 150/75 = 2.
Therefore, the two friends will be 150 miles apart in 2 hours.
Answer:
8
Step-by-step explanation:
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