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alex41 [277]
3 years ago
13

What is the expression for the calculation double the product of 8 and 3

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0
(8*3)2 is correct answer for your question
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Please help i need it
vichka [17]

Answer:

x = 100

Step-by-step explanation:

The area of the left square is 3600

A =s^2

3600 = s^2

Taking the square root of each side

60 =s

The area of the right square is 1600

A =s^2

1600 = s^2

Taking the square root of each side

40 =s

Adding the lengths

60+40 =x

100 =x

3 0
3 years ago
Consider the sequence given by a plus 8 pattern: 2, 10, 18, 26, ….
Finger [1]

Answer:

n = 1 second formula

n = 0 first formula

Step-by-step explanation:

I answer this in the other question you put, here it is again.

This is easy to get. We know the sequence cause it follows a pattern of 8, so let's try some values of n from 1 to 4, to get those numbers with the first formula:

n = 1,2,3,4

f(1) = 8(1) + 2 = 10

f(2) = 8(2) + 2 = 18

f(3) = 8(3) + 2 = 26

f(4) = 8(4) + 2 = 34

As you can see, with the first formula, the first term is 10, and not 2. The only way to get 2 with n = 1 is with the second formula:

f(1) = 8(1) - 6 = 2

f(2) = 8(2) - 6 = 10

f(3) = 8(3) - 6 = 18

f(4) = 8(4) - 6 = 26

With n = 1, the second formula was better and correct.

The first formula could be right only beggining with n = 0. Here is the proof:

f(0) = 8(0) + 2 = 2

6 0
3 years ago
The table shows ticket prices for the local minor
Zanzabum

Answer:

2x club member ticket = 1x non-club member ticket

6 0
3 years ago
Read 2 more answers
Out of 6 cheerleaders, 3 will be selected to match in the first row of the parade. How many 3-person arrangements can be formed
icang [17]
Im pretty sure
A hope this helps
7 0
3 years ago
The graph of the function f(x) = ax^2 + bx + c has vertex at (0, 2) and passes through the point
Ann [662]

Answer:

Step-by-step explanation:

You need to use vertex form of a quadratic to solve this.

Consider the vertex to be (h,k)

Another way of representing a quadratic is in "vertex form":

f(x) = a(x-h)^2+k

Now all you have to do is solve for a.  You know that the vertex is (0,2) and you have know the point of (1,8).  Now, all you have to do is plug in these values and solve for a.

8 = a(1-0)^2+2\\8=a(1)^2+2\\8=a+2\\a=6

Now you know the equation is f(x) = 6(x-0)^2+2 , but you need it in quadratic form.  All you have to do is solve is distribute the 6:

6x^2+2

You get:

a = 6

b = 0

c = 2

Please mark this as brainliest if it satisfies your question

7 0
3 years ago
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