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liq [111]
3 years ago
15

Sixth grade 5.17 Solve percent word problems Yus

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

big d jit

dic dic dic dic dic dic dic di cidic idc

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What od linear algebra exactly?
Alex73 [517]

Answer:

Linear algebra is the study of lines and planes, vector spaces and mappings that are required for linear transforms. It is a relatively young field of study, having initially been formalized in the 1800s in order to find unknowns in systems of linear equations.

<h3>mark me a brainlist</h3>

5 0
3 years ago
What are the odds of drawing a jack or 10 out of 52 cards?
poizon [28]

Answer:

The standard odds of drawing a jack, king, etc is always 1 in 13 from a shuffled 52 card deck. 4 suits,13 cards each, 1 jack for each suit

Step-by-step explanation:

5 0
3 years ago
The two triangles are similar.
prohojiy [21]
I believe it is 60 inches
3 0
3 years ago
Dentify all the pairs of vertical angles in the figure.<br><br> Pair#1:<br><br> Pair#2
Brilliant_brown [7]
Ok so the only ones that we know for sure are 4 = 1, 6=8, 7=9 and you can’t really do all that much with 2,3,5 because it’s not as obvious
3 0
3 years ago
Can someone please explain how to do these?
Pani-rosa [81]

Answer:

<u>First question answer:</u> The limit is 69

<u>Second question answer:</u> The limit is 5


Step-by-step explanation:

For the first limit, plug in x=8 in the expression (9x-3), that's the answer for linear equations and limits.

So we have:

9x-3\\9(8)-3\\72-3\\69

The answer is 69


For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value x=1 into the simplified expression to get the correct answer. Shown below:

\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}

<em>Now putting 1 in x gives us the limit:</em>

\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5

So the answer is 5

3 0
3 years ago
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