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3 years ago

Estimate the product by rounding 9x54

Mathematics

1 answer:

Blizzard [7]3 years ago

3 0

9*54=486

10x50=500

So, either 450 or 500.

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Find the perimeter of the polygon with the vertices A (−1, 1), B (4, 1), C (4,−2), and D(−1,−2).

Brilliant_brown [7]

Given:

The vertices of a polygon are A (−1, 1), B (4, 1), C (4,−2), and D(−1,−2).

To find:

The perimeter of ABCD.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(4-(-1))^2+(1-1)^2}$

$AB=\sqrt{(4+1)^2+(0)^2}$

$AB=\sqrt{(5)^2}$

$AB=5$

Similarly,

$BC=\sqrt{(4-4)^2+(-2-1)^2}=3$

$CD=\sqrt{(-1-4)^2+(-2-(-2))^2}=5$

$AD=\sqrt{(-1-(-1))^2+(-2-1)^2}=3$

Now, perimeter of ABCD is

$P=AB+BC+CD+AD$

$P=5+3+5+3$

$P=16$

Therefore, the perimeter of ABCD is 16 units.

5 0

3 years ago

Show the result of substituting x=0 into 0.75x+1.5y=40

prohojiy [21]

Answer:

y=26.67

Step-by-step explanation:

The given equation is 0.75x+1.5y=40.

We need to show the result of substituting x=0 in above equation.

0.75x+1.5y=40

Put x = 0

0.75(0)+1.5y=40

0+1.5y=40

⇒ 1.5y=4

$y=\dfrac{40}{1.5}\\\\y=26.67$

So, the value of y = 26.67 when x = 0.

8 0

3 years ago

Brainliest if correct<br><br> Solve: 8( 4 - 2^{6} divided by 4)

polet [3.4K]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{8(4 - 2^6)}{4}}$

$\mathsf{2^6}\\\mathsf{\rightarrow2\times2\times2\times2\times2\times2}\\\mathsf{\rightarrow 4\times4\times4}\\\mathsf{\rightarrow 16\times4}\\\mathsf{\rightarrow \bf 64}$

$\mathsf{= \dfrac{8(4 - \bf 64)}{4}}$

$\mathsf{4 - 64}\\\mathsf{\rightarrow \bf -60}$

$\mathsf{= \dfrac{8(\bf -60)}{4}}$

$\mathsf{8(-60)}\\\mathsf{\rightarrow \bf -480}$

$\mathsf{= \dfrac{-480}{4}}\\\\\mathsf{\rightarrow \dfrac{-480\div4}{4\div4}}\\\\\mathsf{\rightarrow- \dfrac{\bf 120}{1}}\\\\\mathsf{\rightarrow \bold{-120}\div 1}}\\\\\mathsf{\rightarrow \bf -120}$