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nadezda [96]
3 years ago
11

What is 200 x 4 for math class

Mathematics
2 answers:
kobusy [5.1K]3 years ago
6 0

Answer: Your answer is 800

Step-by-step explanation: Hope this helped you

AURORKA [14]3 years ago
4 0

Answer:

800

Step-by-step explanation:

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how can I find the smallest division of a measurement without a ruler? for eg. 12.45cm, what's the smallest division? ​
vladimir1956 [14]

Answer:

Step-by-step explanation:

mm

5 0
3 years ago
Natasha has four nickels to dimes and 6 quarters in her pocket what is a theological probability that she will randomly select a
My name is Ann [436]

Answer:

1/2

Step-by-step explanation:

There are 4 nickels, 2 dimes, and 6 quarters. That means a total of 12 coins, half of which are quarters.

(realistically, if she wanted to, she could probably get a quarter every time if she felt for the size)

4 0
3 years ago
Read 2 more answers
As part of a school science project, Jacob bought some bulbs for a total of $18. The cost of each bulb was $3. How many bulbs di
MA_775_DIABLO [31]
3 x 6 = 18
3 + 3 + 3+ 3 + 3 + 3 = 18
3 divided by 18 = 6
I wasn't sure how you were doing it, so I just a few references for you. Jacob bought 6 light bulbs
Hope this helps!
5 0
4 years ago
How many solutions does the following equation have? 4(y-30)=4y+124(y−30)=4y+12
dedylja [7]

Answer:

A. No solution

Step-by-step explanation:

Choose 1 answer:

A. No solutions

B. Exactly one solution

C. Infinitely many solutions

Solution

Given:

4(y-30)=4y+12

Open parenthesis

4y-120=4y+12

Collect like terms

4y-4y=12+120

0=142

There is no solution to the equation, therefore, the answer is A

4 0
3 years ago
A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam
bekas [8.4K]

Answer:

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given data random sample of 46 bins, the sample mean amount was 49.9 pounds and the sample standard deviation was 3.641

<em>The sample size 'n' =46</em>

<em>mean of the sample x⁻ = 49.9</em>

<em>Standard deviation of the sample S = 3.641</em>

<u>Confidence intervals:</u><em>-</em>

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

<em></em>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })<em></em>

<em>Degrees of freedom = n-1  = 46-1 =45</em>

<em>The tabulated value   t₀.₉₆ =   1.794 ( from t-table)</em>

<em></em>(49.9 - 1.794 \frac{3.641}{\sqrt{46} } ,49.9+ 1.794 \frac{3.641}{\sqrt{46} })<em></em>

(49.9 -0.9630 , 49.9+0.9630)

(48.937 , 50.863)

<u>Conclusion:</u>-

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

4 0
3 years ago
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