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EastWind [94]
3 years ago
6

-6 (y + 15) = -3y + 6 What value of y makes the equation true?

Mathematics
1 answer:
wolverine [178]3 years ago
8 0

Answer: y=-32

Step-by-step explanation:

1. Simplify:

-6y-90=-3y+6

2. Add like terms:

-96=3y

=> y=-32

Have a nice day! :)

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Which set of ordered pairs belongs to a linear function?
masya89 [10]

Answer:

<u><em>Hi there the correct answer will be is B)  (-1,5), (1, 3), (3, 1), (5,0)</em></u>

hope it helps to your question!

7 0
3 years ago
Determine whether 5n2 or 3n will have the greater value when:<br><br><br><br> a. n = 1
densk [106]

Answer:

5n2 will have a greater value

Step-by-step explanation:

5n2

5x1x2=10

3n

3x 1= 3

5 0
3 years ago
You wish to find a 95% confidence interval for the mean number of times men change channels with a remote control during a comme
gogolik [260]
For margin of error to be a maximum of 3:
3 = z*(SD / sqrt(n)), where z is the z-score, SD is the standard deviation and n is the sample size.
z = 1.96 for a 95% confidence interval, and we are given SD = 15.
3 = 1.96*15/sqrt(n)
sqrt(n) = 9.8
n = 96.04 ~ 96 commercials.

4 0
3 years ago
Which table represents the graph of a logarithmic function in the form y=log3x when b&gt;1?
alex41 [277]

Answer:

<u><em>The satisfied table of the given function</em></u>y = log_{b} (x)<u><em></em></u>

<em>x                    1/8            1/4             1/2              1             2</em>

<em>y                    -3                 -2            -1               0               1</em>

<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function y = log_{b} (x)   if b >1

Given first table

i)

put x = \frac{1}{8}     given b > 1 so we can choose b = 2

y = log_{2} (\frac{1}{8} )

y = log_{2} (2^{-3}  )

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-3}  ) = -3 log_{2} (2) = -3 (1) = -3

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em>\frac{1}{4}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{4} )<em></em>

<em></em>y = log_{2} (2^{-2}  )<em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-2}  ) = -2 log_{2} (2) = -2 (1) = -2

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em>\frac{1}{2}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{2} )<em></em>

y = log_{2} (2^{-1}  )

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

y = log_{2} (2^{-1}  ) = -1 log_{2} (2) = - (1) = -1

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (1 )<em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em>2<em>     given b > 1 so we can choose b = 2</em>

y = log_{2} (2 )

<em>y = 1</em>

<em></em>

<u><em>Final answer:-</em></u>

<u><em>The satisfied table of the given function</em></u>

<em>x                    1/8            1/4             1/2              1             2</em>

<em>y                    -3                 -2            -1               0               1</em>

<em></em>

8 0
3 years ago
Read 2 more answers
Round 607.5 to the nearest whole number.
kari74 [83]
608

607.5

.5 rounds up to 1

607+1=608
7 0
3 years ago
Read 2 more answers
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