Question

Use the completing the square to solve x^2+6x=12.

Answer 1

Answer:

x= -3 ± $\sqrt{21}$

Step-by-step explanation:

$x^{2}$+6x=12

We add 9 [$(6/2)^{2}$] to both sides to complete the square as $x^{2}$+6x+9 = $(x+3)^{2}$.

$(x+3)^{2}$=21

Now we take the square root of both sides:

x+3=±$\sqrt{21}$

x= -3 ± $\sqrt{21}$

Answer 2

Answer:

x = -3 ± $\sqrt{21}$

Step-by-step explanation:

$x^2+6x=12$

$(\frac{b}{2} )^{2}$ = 9

$x^2+6x + 9 =12 + 9$

$(x+3)^{2} =21$

x + 3 = $\sqrt{21}$

x = -3 ± $\sqrt{21}$