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2 years ago

12

Spencer is going snowboarding. He rode the ski lift to the top of the mountain,

1 answer:

Marina CMI [18]2 years ago

5 0

Not sure but good luck 25•

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(x + y + 2)(y + 1)<br> Solve

RideAnS [48]

Hello there! We are given the following equation and want to simplify it:

$(x+y+2)(y+1)$

First, let's use the Distributive Property:

$(a+b)(c)=ac+bc$

For this step, we are going to let:

$a=y$

$b=1$

$c=(x+y+2)$

After applying this version of the Distributive Property, we are given the equation:

$(y)(x+y+2)+(1)(x+y+2)$

We're going to use the distributive party again, but a slightly different version that's almost the same as first:

$(a)(b+c+d)=ab+ac+ad$

Using this on both terms of the equation changes the equation to:

$(xy+y^2+2y)+(x+y+2)$

Now, we just remove the parenthesis and combine like terms

$y^2+3y+xy+x+2$

This should be your answer. Let me know if you need any clarifications, thanks!

~ Padoru

6 0

2 years ago

Which one is it?<br> A, B, C, or D?

grigory [225]

Answer: I'd go with C

Step-by-step explanation:

3 0

3 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

2 years ago

Donald spends a total of $17.43 on peanuts that cost $2.49 per pound. How many pounds of peanuts does he buy?

True [87]

Answer:

He bought 7 pounds of peanuts

Step-by-step explanation:

17.43/2.49=7

4 0

2 years ago

What is the quotient of 25÷6

timama [110]

25 is the quotient I think haven't done this in 5 years

7 0

2 years ago

Read 2 more answers