Help!!!!!! I’ve been working on this for 1 hour
1 answer:
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Use Law of Cooling:
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM