Answer:
45.45 batteries
Step-by-step explanation:
The probability of any random battery being defective is 1 in 11, the number of expected defects in a population of 500 batteries is given by:
45.45 batteries are expected to be defective.
Answer:
9/12 and 6/8
Step-by-step explanation:
Answer:
y^2+8y+16
Step-by-step explanation:
6y^2 +2y +5 - ( 5y^2 -6y-11)
Distribute the minus sign
6y^2 +2y +5 - 5y^2 +6y+11
Combine like terms
y^2+8y+16
43 percent
1$ is equal to 100 cents, so 43 cents out of 100 cents, or 43/100 equals 43 percent
Answer:
22.5 years to the nearest tenth.
Step-by-step explanation:
The equation is
6000 = 4000(1 + 0.018/12)^12t where t = the number of years
(1 + 0.018/12)^12t = 1.5
1.0015^12t = 1.5
Taking logs:
12t log 1.0015 = log 1.5
12t = log 1.5 / log 1.0015
12t = 270.51
t = 22.54 years.
