To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that <em>W </em>is the width and <em>L </em>the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this: $A_{total} = (L+6)(W+6)$ .

In addition, we know that the total area is 970 and the length is 8 ft longer than the width ( $L=W+8$ ). So:

$A_{total} = (L+6)(W+6)\\970 = (W+8+6)(W+6)\\970=W^{2}+20W+84\\W^{2}+20W-886=0$

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: $W_{1}=21.4$ and $W_{2}=-41.4$

Therefore, the width is 21.4 ft, because the negative number cannot represent distances.

Using the relation between length and width:

$L=W+8\\L=21.4+8=29.4$

<em>Therefore, the dimensions of the pool are 29.4 length and 21.4 width.</em>

7 0

2 years ago

What are two fractions that equal -7/10?

kobusy [5.1K]

Answer:

-14/20

-21/30

Step-by-step explanation:

-7/10

-7x2=-14 and -10x2=-20

-14/20

-7/10

-7x3=-21 and -10x3= -30

-21/30

3 0

2 years ago