If one of the outer corners of an isosceles triangle is 115 degrees, then the internal angle is 180-115 = 65 degrees.
The task has 2 solutions.
Let the angle at the vertex is 65 degrees. Then the angles at the base are (180-65): 2 = 57.5 degrees.
Let the angle at the base be 65 degrees, then another angle at the base is 60 degrees. The vertex angle is 180- (65 + 65) = 50 degrees.
Answer:
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