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3 years ago

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IF CD=AD, and CB=AD. Then 1=2

1 answer:

Natalka [10]3 years ago

7 0

Answer:

thanks for free points

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Bir sayinin 3 fazlasinin 2 katı ile ayni sayinin 2 katinin 3 fazlasinin toplami 23 e eşittir. buna gore assagidakilerden hangisi

sesenic [268]

Answer:

English plz

Step-by-step explanation:

3 0

3 years ago

Samuel rotated PLUTO 90° clockwise about the origin to generate P'L'U'T'O'.

NeTakaya

Answer:.

Step-by-step explanation:

5 0

3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago

Which expression is equivalent to x y Superscript two-ninths?

crimeas [40]

Option D: $x\sqrt[9]{y^2}$ is the expression equivalent to $xy^{\frac{2}{9}}$

Explanation:

Option A: $\sqrt{xy^9}$

The expression can be written as $({xy^9})^{\frac{1}{2}$

Applying exponent rule, we get,

$x^{\frac{1}{2}} y^{\frac{9}{2}}$

Thus, the expression $\sqrt{xy^9}$ is not equivalent to the expression $xy^{\frac{2}{9}}$

Hence, Option A is not the correct answer.

Option B: $\sqrt[9]{xy^2}$

The expression can be written as $({xy^2})^{\frac{1}{9}$

Applying exponent rule, we get,

$x^{\frac{1}{9}} y^{\frac{2}{9}}$

Thus, the expression $\sqrt[9]{xy^2}$ is not equivalent to the expression $xy^{\frac{2}{9}}$

Hence, Option B is not the correct answer.

Option C: $x\sqrt{y^9}$

The expression can be written as $x(y^9)^{\frac{1}{2} }$

Applying exponent rule, we get,

$x y^{\frac{9}{2}}$

Thus, the expression $x\sqrt{y^9}$ is not equivalent to the expression $xy^{\frac{2}{9}}$

Hence, Option C is not the correct answer.

Option D: $x\sqrt[9]{y^{2} }$

The expression can be written as $x(y^2)^{\frac{1}{9} }$

Applying exponent rule, we get,

$xy^{\frac{2}{9}}$

Thus, the expression $xy^{\frac{2}{9}}$ is equivalent to the expression $xy^{\frac{2}{9}}$

Hence, Option D is the correct answer.

4 0

3 years ago

Read 2 more answers

How to find the volume

aev [14]

Answer: 1.44 centimeters cubed.

Step-by-step explanation:

To find the volume of a rectangular prism, use the following formula:

$V=whl$ , where w equals the width, h equals the height, and l equals the length.

Substituting 0.6, 1, and 2.4 for the variables:

V = 0.6 * 1 * 2.4

V = 1.44 cm^3

The volume of the prism is 1.44 centimeters cubed.

7 0

3 years ago