Answer:
70
Step-by-step explanation:
Let's start by writing a system of linear equations:
c -> cookies
cb -> candy bars
(You can use any abbreviations to your preference)
Abby:
4 cookies
3 candy bars
$10.25 per bag
The equation would be:
4c+ 3cb = $10.25
Marissa:
2 cookies
7 candy bars
$14.75 per bag
The equation would be:
2c + 7cb = $14.75
So our linear equation system would be:
<span>4c+ 3cb = $10.25
</span><span>2c + 7cb = $14.75
I would try to get rid of one variable so I can solve for the other variable. In this case, it is easier to get rid of c since I can multiply the second equations by 2. Then it would subtract the two equations.
(2c + 7cb = $14.75) 2 = 4c + 14 cb = $29.50
4c + 3cb = $10.25
- 4c+14 cb = $29.50 (4c would get canceled.)
---------------------------------
-11 cb = - $19.25 (Divide by -11 to solve for cb)
</span> --------- -------------
-11 -11
cb = $1.75
Now we know cb (candy bar) cost, we would substitute this value into cb into one of the equations. It doesn't matter which equation you put it in. I will substitute it in the first equations.
4c + 3 (1.75) = $10.25
4c + 5.25 = $10.25 (Multiply 3 by 1.75)
-5.25 -5.25 (Subtract 5.25 on both sides)
4c = 5 (Divide by 4 on both sides to get c)
---- ---
4 4
c= 1.25
Check the work:
4(1.25) + 3(1.75)
= $10.25
2(1.25) + 7(1.75)
= $14.75
Total cost:
cookies = $1.25
candy bars = $ 1.75
Hope this helps! :)
Answer:
8 + k² - 6 > 8(k + 2) - 4k when k = 7
Step-by-step explanation:
8 + k² - 6 = 8 + 7² - 6 = 51
8(k + 2) - 4k = 8(7 + 2) - 4(7) = 8(9) - 28 = 44
8 + k² - 6 > 8(k + 2) - 4k when k = 7
A bag contains four red marbles, two Yellow Marbles and five blue marbles.
Two marbles are drawn at random without replacement.
Total number of marbles are,

There are 11 ways to select first marble and 10 ways to select second marble.
The total number of possible outcomes are calculated as,

Thus the total number of possible outcomes are 110.
Answer:
3
Step-by-step explanation:
We know x = -2, so we can substitute -2 in for x
3x^2- 9
3*-2^2-9
Solve the exponent first (PEMDAS)
3*4-9
Multiply next
12-9
Subtract
3