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2 years ago

Please help quickly, if someone answers quickly I'll give them Brainly.

Mathematics

2 answers:

Ugo [173]2 years ago

7 0

Step-by-step explanation:

Ratio

= Difference between Prediction and Actual / Prediction

= (99 - 88)/99 = 11/99.

Percentage Error

= Difference between Prediction and Actual * 100%

= (99 - 88) * 100% = 11.1%. (1)

denis-greek [22]2 years ago

6 0

1. A

I hope this helped! This is because the division of numbers and factors are equal to this.

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3 years ago

Researchers at Gallup were interested in whether there was a decrease in the proportion of nonretirees (in other words, people w

Lera25 [3.4K]

Answer:

A. We have extremely strong evidence to reject H0.

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3 years ago

What is the value of the dicsriminant of x^2-7x+4?

Aleks [24]

Answer:

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3 years ago

Does anybody know how to do time with exponential decay

My name is Ann [436]

<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

$b_n=0.12\times b_{n-1}$

Why does this work? Initially, you start with 500 mL of air that you breathe in, so $b_1=500\text{ mL}$ . After the second breath, you have 12% of the original air left in your lungs, or $b_2=0.12\timesb_1=0.12\times500=60\text{ mL}$ . After the third breath, you have $b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}$ , and so on.

You can find the amount of original air left in your lungs after $n$ breaths by solving for $b_n$ explicitly. This isn't too hard:

$b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots$

and so on. The pattern is such that you arrive at

$b_n=0.12^{n-1}b_1$

and so the amount of air remaining after $50$ breaths is

$b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}$

which is a very small number close to zero.</span>

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3 years ago