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vovangra [49]
3 years ago
15

Nknjjhbvyugvtfituyjnjjjjjnnnnj

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

indeed

Step-by-step explanation:

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Determine the margin of error for a 99​% confidence interval to estimate the population proportion with a sample proportion equa
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Which of the following methods of timekeeping is the least precise?
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Rewrite in simplest terms: -4(5v – 3v – 6) – 9v
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-4 (5v -3v -6) -9v (use the distributive property)

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-17v +24

3 0
3 years ago
Read 2 more answers
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
A number d minus is less than -1
katrin [286]

\boxed{d-4

<h2>Explanation:</h2>

Hello! Recall you need to write complete questions in order to find exact answers. So in this problem I'll assume the question is:

<em>A number d minus 4 is less than -1</em>

<em />

So it is easy to know that we need to write an inequality here because of the words "less than", which implies that we must use the symbol <. So let's solve this step by step.

Step 1. A number d minus 4.

This statement includes the word "minus", so we need to use the symbol (-). Therefore:

d-4

Step 2. A number d minus 4 is less than

As we said above, here we need to use the symbol (<). So:

d-4

Step 3. A number d minus 4 is less than -1

Finally, we get:

d-4

<h2>Learn more:</h2>

Inequalities: brainly.com/question/9611462

#LearnWithBrainly

3 0
3 years ago
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