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rodikova [14]
3 years ago
15

Suppose you can factor x^2 +bx +c as (x+p)(x+q) . If c<0, what could be the possible values of p and q?

Mathematics
2 answers:
Anna11 [10]3 years ago
4 0
Ans: Option A

Explanation:
Let's solve it smartly!
Given expression: x^{2} + bx +c --- (A)
Factors: (x+p)(x+q)
Condition: c<0
Now let us expand (x+p)(x+q):
=> x^{2} + (p+q)x + pq  --- (B)

By comparing (B) with (A), we can say that:
pq = c --- (C)

Now, as the condition says, c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.

1) If p>0, q>0, it means c>0 since (+p)(+q) = (+c)(according to equation (C)). Condition is not met.
Hence, option B and D are wrong.

2) If p<0, q<0 it means c>=0 since (-p)(-q) = (+c)(according to equation (C)). Condition is not met.
Hence option C is out as well.

We are left with Option A:p<0, q>0 it means c<0 since (-p)(+q) = (-c)(according to equation (C)).
Condition is MET!
Hence,
Ans: Option A: p= -3, q= 7
DIA [1.3K]3 years ago
4 0
answer A is the answer
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2x + 5y = 8<br> x - 2y = -5<br> Simultaneously pleasee
mario62 [17]

Answer:

(- 1, 2 )

Step-by-step explanation:

2x + 5y = 8 → (1)

x - 2y = - 5 → (2)

multiplying (2) by - 2 and adding to (1) will eliminate x

- 2x + 4y = 10 → (3)

add (1) and (3) term by term to eliminate x

0 + 9y = 18

9y = 18 ( divide both sides by 9 )

y = 2

substitute y = 2 into either of the 2 equations and solve for x

substituting into (1)

2x + 5(2) = 8

2x + 10 = 8 ( subtract 10 from both sides )

2x = - 2 ( divide both sides by 2 )

x = - 1

solution is (- 1, 2 )

3 0
2 years ago
Read 2 more answers
Are these ratios equivalent?
Debora [2.8K]
<h3>Answer:  Yes</h3>

========================================================

Explanation

The ratio 8:10 simplifies to 4:5 when you divide both parts by 2.

The ratio 16:20 simplifies to 4:5 when you divide both parts by 4

Therefore the two ratios 8:10 and 16:20 are both equal 4:5, so they are equal to one another.

------------

Put another way,

(8 large)/(10 small) = (16 large)/(20 small)

8/10 = 16/20

8*20 = 10*16 ... cross multiply

160 = 160

We get a true equation, so the first equation is true as well.

This shows the ratios are equivalent.

-------------

Or you could have...

(8 large)/(16 large) = (10 small)/(20 small)

8/16 = 10/20

8*20 = 16*10

160 = 160

We get the same conclusion as before.

3 0
2 years ago
Can someone please help my math assignment is due in 4 hours and I have no idea how to do these 2 problems
Nitella [24]

Answer:

hmmm

Step-by-step explanation:

I think its 3-5

8 0
3 years ago
How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, if repetition of digits is not allowed? a.119 b.16,
Sergeeva-Olga [200]
Answer:
c. 2520

Explanation:
Repetition is not allowed, therefore:
1st digit can be any of the given 7 numbers
2nd digit can be any of the remaining 6 numbers
3rd digit can be any of the remaining 5 numbers
4th digit can be any of the remaining 4 numbers
5th digit can be any of the remaining 3 numbers
This means that:
number of possible combinations = 7 * 6 * 5 * 4 * 3 = 2520 numbers

Hope this helps :)
5 0
3 years ago
Find the equation of the line.
Ymorist [56]

Answer:

y = 0,5 x + (-3)

Step-by-step explanation:

We can see from the graph that when y = -3, the line crosses y axis, therefore

y = ? x + (-3)

We can also spot that when x = 6, y = 0

// now mark ? sign as a variable k and put the given x and y values into the previous expression

y = k * x - 3

0 = k * 6 - 3

k * 6 = 3

k = 3/6

k = 0,5

3 0
2 years ago
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