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Andreas93 [3]
3 years ago
8

Graph the image of parallelogram EFGH after a translation 9 units left and 1 unit up.​

Mathematics
2 answers:
In-s [12.5K]3 years ago
6 0

Answer:

Kagat at himud is here to help you

Vinil7 [7]3 years ago
6 0
Answer below
...................

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I’ll Mark u as brainless if you solve this
Contact [7]

i think the person below me is correct and the answer is 12

4 0
3 years ago
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Raquel works in a pet store every day after school and sometimes on weekends. She earns $5.20 per hour. If Raquel works 21 hours
riadik2000 [5.3K]

Answer:

B

Step-by-step explanation:

$5.20 is about $5.00, 21 is about 20, so $5.00 * 20 *4 = $400.

Checking this: $5.20 * 21 * 4 = $436.80

8 0
2 years ago
Read 2 more answers
X to the 2 power -6 when X = -14
riadik2000 [5.3K]
-14x-14 = 196 then subtract -6 from 196 because they'll cancel each other out. the answer is 190.
8 0
3 years ago
Helppppppppppppppppppppppppp
kumpel [21]
Answer:
x = 10

Explanation:
Note the following rules before we begin:
2 ln(a) = ln (a²)
ln (a) + ln (b) = ln (ab)

Now, for the given:
ln(20) + ln(5) = 2 ln(x)
ln(20*5) = ln(x²)
ln(100) = ln(x²)

This means that:
100 = x²
Therefore:
either x = 10 .........> acceped
or x = -10 .........> rejected as no negatives are allowed within ln functions

Hope this helps :)
5 0
3 years ago
A child lets go of a balloon that rises at a constant rate. 5 seconds after it was released, the balloon is at a height of 16 fe
Mama L [17]

Answer:

1. h = 2.4t + 4

2. 4 feet

3. 220 feet

Step-by-step explanation:

1. Write a linear model for the height, h, of the balloon as a function of the number of seconds, s that it has been raising.

Since the balloon rises at a constant rate, we find this rate by using the initial and final values of height and time at 5 seconds and 20 seconds respectively which are 12 feet and 52 feet respectively.

So, rate = gradient of line

= change in height/change  in time

= (52 ft - 16 ft)/(20 s - 5 s)

= 36 ft/15 s

= 2.4 ft/s

Now the equation of the line which shows the height is gotten from

(h - h')/(t - t') = rate

Using h'= 16 feet and t' = 5 s, we have

(h - 16)/(t - 5) = 2.4

h - 16 = 2.4(t - 5)

h - 16 = 2.4t - 12

h = 2.4t - 12 + 16

h = 2.4t + 4

where h is the height of the balloon above the ground and t is the time spent in the air in seconds.

2. What was the height of the balloon initially before the child let it go?

We obtain the initial height of the balloon before the child let go at time, t = 0 the time before the child let go.

So, substituting t = 0 into the equation for h, we have

h = 2.4t + 4

h = 2.4(0) + 4

h = 0 + 4

h = 4 feet

So, the height of the balloon before the child let go is 4 feet above the ground.

3. Use your model to predict the height of the balloon after 90 seconds.

We insert t = 90 s into the equation for h. So,

h = 2.4t + 4

h = 2.4(90) + 4

h = 216 + 4

h = 220 feet

So, the height of the balloon after 90 s is 220 feet above the ground.

8 0
2 years ago
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