Answer:
skip counting by 0
Step-by-step explanation:
skipcount by 0 to get to 100 for the third column.
Answer:
7a^4b^3
Explanation/Steps to solve:
First you separate 49 and 21 from the variables. Then you find their GCF.
The GCF of 49 is 21 is 7.
Then you find the GCF of the variables.
a^4b^3 and a^4b^5
how many As and Bs do they have in common?
both variables have 4 As and both have 3 Bs. <u><em>It can't be 5 Bs since the other variable only has 3. 3 is less than 5 which means that there can be a 3 in the other variable (b^5).</em></u>
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So we rewrite how much As and Bs they have.
4 As = a^4
3 Bs = b^3
---> a^4b^3
then we combine both the GCF of the numbers and the variables,
7a^4b^3
Answer:
As the size of a school building increases, the number of student musicians increases because the scatterplot has a cluster that increases from left to right.
Step-by-step explanation:
Answer:
1 / 2
Step-by-step explanation:
Cos 60°
= 1 / 2
1 / 2 is the answe.
