<u>ANSWER: </u>
x-intercepts of 
<u>SOLUTION:</u>
Given,
-- eqn 1
x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.
Now, let us find the zeroes using quadratic formula for f(x) = 0.

Here, for (1) a = 1, b= 12 and c = 24


Hence the x-intercepts of 
Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
Answer:
Step-by-step explanation:
4 and a half
It's dependent on the context. A book may ask you to find the f'(x) of a function and you may have to use a u sub in your problem which requires you to find the dy/dx of what you substitute. So in this case both would be used.
Bla bla bla your answer is x=4.95