Answer: P(6/7G) = 729⁄16384 = 0.044
The probability of having exactly six seeds germinate is 0.044
Complete Question:
A certain seed has 75% germination rate. Of seven seeds are planted, find the probability of having exactly six seeds germinate.
Step-by-step explanation:
The probability that a seed will germinate is
P(G) = 0.75
The probability that a seed will not germinate is
P(G') = 1-0.75 = 0.25
Therefore the probability that only 6 will germinate can be written as;
P(6/7G) = the probability that 6 seed germinate × the probability that one seed will not geminate
P(6/7G ) =[ P(G)]^6 ×[ P(G')]
P(6/7G) = 0.75^6 × 0.25
P(6/7G) = 729⁄16384 = 0.044
1. 5 <span>> 0
2. -1 </span><span>> -2
3. -3 </span><span>< 4
4. -2 </span>> -3
5. 0 > -1
6. -6 = -6
7. 0 < 7
8. -5 < -1
9. -10 < 9
10. -10 > -20
11. 5 = 5
12. -12 < 9
Answer:
The answer to your question is (-4, 9) and (3, 2)
Step-by-step explanation:
Data
Equation 1 y = x² - 7
Equation 2 y = -x + 5
Process
1.- Substitute Equation 2 in equation 1
-x + 5 = x² - 7
2.- Equal to zero
x² + x - 7 - 5 = 0
x² + x - 12 = 0
3.- Factor to find x
(x + 4)(x - 3) = 0
x₁ + 4 = 0 x₂ - 3 = 0
x₁ = -4 x₂ = 3
4.- Substitute x₁ and x₂ to find y
y = -x + 5 x₁ = -4
y = -(-4) + 5
y = 4 + 5
y = 9 Solution (-4, 9)
y = -x + 5 x₂ = 3
y = -3 + 5
y = 2 Solution (3, 2)
So distributive=ab+ac=a(b+c)
so
find the gcf of 4 and 12
4=2 time 2
12=2 times 2 times \3
the gcf is 2 times 2 =4
4(d+3e)
Let x be the money he had originally.
x/3+5=x/2
5=x/6
x=30
So he had $30 originally.
