Answer:
(301)^2-(300)^2
it is in the form of
a^2-b^2=(a+b)(a-b)
so,
(301+300)(301-300)
(601)(1)=601
the exponential function f(x) =
he invest $1000 for 5, 10, 15 years
5 years,
To find the amount of money he have , we plug in 5 for x and find out f(5)
f(x) =
f(5) =
= 1762.34
The amount of money he have after 5 years is 1762.34
10 years,
To find the amount of money he have , we plug in 10 for x and find out f(10)
f(10) =
= 3105.85
The amount of money he have after 10 years is 3105.85
15 years,
To find the amount of money he have , we plug in 15 for x and find out f(15)
f(15) =
= 5473.57
The amount of money he have after 15 years is 5473.57
f(5) = 1762.34
f(10) = 3105.85
f(15) = 5473.57
Answer:
2
Step-by-step explanation:
Because it goes into the positives and then comes out to be 2
Question 1)
Gwen has already burned 100 calories when Tristan and Keith started, and he continues to burn 10 calories per minute. The equation for Gwen is
y = 100 + 10x
Question 2)
`Tristan is burning 125 calories every 10 minutes. His burning calories rate is 12.5 calories per minute. The equation for Tristan is
y = 12.5x
Question 3)
Keith is burning 300 calories in 30 minutes. His rate per minute is 10 calories per minute. The equation for Keith is
y = 10x