Step-by-step explanation: Arrange the terms in ascending order: -7, -2/5, 3/9, 11/12.
Hope this helps! :D
-TanqR
The distance from the sun is option 2 5.59 astronomical units.
Step-by-step explanation:
Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.
Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power 
is on the variable we need to find so we multiply both the sides by an exponential power of 
to be able to calculate 'a'.
P = 
, 
= 
, = a, 
= a = 5.58533 astronomical units.
Rounding it over to nearest hundredth we get 5.59 astronomical units.
The third one because as x increases, y decreases and all the points are around a single line
Answer: Your picture will not show up, can you post again?
Step-by-step explanation:
Answer:
A)0.86
B)0.99
C)6.047E-13
Step-by-step explanation:
Since p = 0.01 and q= 0.99
Number of event n = 15
Using binomial expansion
A) Probability (No samples are mutated) = 15C0 (p)^0 * (q)^15
= 1*(0.01)^0*(0.99)^15 = 0.86
B)Probability (At most one sample is mutated) = 15C0 * p^0 *q^15 + 15C1 * p^1 * q^14 = 1*(0.01)^0*(0.99)^15 + 15C1 * 0.01 * 0.99^14 = 0.86 + 15*0.01*0.8687 = 0.86 + 0.13 = 0.99
C) Probability (More than half the samples are mutated) = 15C8* 0.01^8 * 0.99^7 + 15C9* 0.01^9 * 0.99^6 +15C10* 0.01^10 *0.99^5 + 15C11 * 0.01^11 * 0.99^4 + 15C12 * 0.01^12 * 0.99^3 + 15C13 * 0.01^13 * 0.99^ 2 + 15C14 * 0.01^14 * 0.99^1 + 15C15 * 0.01^15 * 0.99^0
Probability (More than half the samples are mutated) = 6E-13 + 4.71E-15 + 2.86E-17 + 1.31E-19 + 4.41E-22 + 1.03E-24 + 1.49E-27 + 1E-30 = 6.047E-13
