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Lorico [155]
3 years ago
11

Help answer this im struggling omg

Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0
H^2 + 3.5 = 20^2

That is the formula
Svetlanka [38]3 years ago
7 0

Answer:

im not quite sure but what i got was 19.9

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Combine like terms.<br> (x+6)(x+6)
ycow [4]

Answer:

(x+6)(x+6)

(x+6)^2

Always remember this identity

(a+b)^2 = a^2 + b^2 + 2ab

So, Now take x=a , 6 =b

Substitute above values

x^2 + 36 +2(x)(6)

=x^2 +36 +12x

=x(x+12) +36

5 0
2 years ago
Read 2 more answers
Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What
777dan777 [17]

Answer:

B) \frac{3}{4} x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

                               = 40 units

Dilating KMPT by a scale factor of \frac{3}{4} would create K'M'P'T' of dimensions; \frac{3}{4} × 12 units by \frac{3}{4} × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

                                  = 2(9 + 6)

                                  = 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be  \frac{3}{4} × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

         perimeter of K'M'P'T' = \frac{3}{4} * x units

                                            = \frac{3}{4}x units

6 0
3 years ago
Help someone out pls!
likoan [24]

Answer: the answer is D

Step-by-step explanation:V = pi (d/2)^2  *  h

V =  pi  (d^2  / 4)   * h

 h =  4V  /  ( pi  * d^2)       (meters) 

6 0
1 year ago
Solve 5n^2=5 with the quadratic formula
Yanka [14]

Answer:

n = 1

Step-by-step explanation:

First, rearrange the equation to standard form 0 = ax² + bx + c, when everything equals 0.

5n² = 5

5n² - 5 = 0

State the variables a, b and c.

a = 5;  b = 0;  c = -5

Substitute a, b, and c into the quadratic formula.

n = \frac{-b ±\sqrt{b^{2}-4ac} }{2a}

n = \frac{-0 ±\sqrt{0^{2}-4(5)(-5)} }{2(5)}   Substitute

n = \frac{\sqrt{100} }{10}   Simplify inside the √ and bottom

n = \frac{10}{10}  Simplify the top

n = 1  Final answer

Therefore the solution is n = 1.

The quadratic formula usually is written with x, but it can be solved with any variable in standard form.

3 0
3 years ago
Without using paper and pencil, how would you find the sum of 23 and 37?
ankoles [38]
You could use a calculator, or do mental math.  
8 0
3 years ago
Read 2 more answers
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