Answer: A and C are the correct answers
Step-by-step explanation:
Your welcome ;)
SOLUTION
From the question, the center of the hyperbola is
a is the distance between the center to vertex, which is -1 or 1, and
c is the distance between the center to foci, which is -2 or 2.
b is given as
![\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2%3Dc%5E2-a%5E2%20%5C%5C%20b%5E2%3D2%5E2-1%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
But equation of a hyperbola is given as
Substituting the values of a, b, h and k, we have
![\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%28x-0%29%5E2%7D%7B1%5E2%7D-%5Cfrac%7B%28y-0%29%5E2%7D%7B%5Csqrt%5B%5D%7B3%7D%5E2%7D%3D1%20%5C%5C%20%5Cfrac%7Bx%5E2%7D%7B1%7D-%5Cfrac%7By%5E2%7D%7B3%7D%3D1%20%5Cend%7Bgathered%7D)
Hence the answer is
Answer:
Total pints of cream will they need for the pasta = 7 pints
Step-by-step explanation:
Given - Pasta Place needs to make pasta with garlic cream sauce for 80 guests at a party. One batch of pasta calls for 3 cups of cream and feeds 10 people. The restaurant already has 5 pints of cream in the fridge.
To find - How many more pints of cream will they need for the pasta?
Solution -
10 people = 3 cups of cream
⇒80 people = 8×3 = 24 cups of cream
Now,
We know that,
1 cup = 0.5 pints
⇒24 cup = 24×0.5 = 12 pints.
Now,
Given that, The restaurant already has 5 pints of cream in the fridge.
So,
Total pints more needed = 12 - 5 = 7 pints.
∴ we get
Total pints of cream will they need for the pasta = 7 pints
The mean is simply the average of the data set.
Mean = (3+4+6+7+9+9+11)/7 = 7
The median, on the other hand, is the middle data when you arrange them from least to greatest. The middle data here is 7.
Hence, initially, the mean and median are equal. In order to make the mean less than median, add another data point which makes it the lowest. For example, we can add 1 as the new data point. The mean would be:
Mean = (1+3+4+6+7+9+9+11)/8 = 6.25
The median is (6+7)/2 = 6.5
Therefore, you can add any number less than 3. For example, that could be 1.
