A linear relationship between two quantities will produce a graph of a straight line. ... In order to create the line, we use the function equation and evaluate the range, or output, values based upon several of the domain, or input, values.
So hmm if you notice the picture below
between 2 and 16, there are 14 units, so, the center is half-way in between, thus, is at y = 7, or -2, 7
because, the major axis is over the y-axis, then the "a" component, goes under the fraction with the "y" in the numerator
I would do
x = number of books on saturday
2 = every day
so...
(x2)
Answer:
B
Step-by-step explanation:
It isn't A. A has to be something like y = -x^2 That minus sign directs the parabola downward.
It could be B which is something like y = x^3 - 5
C has an odd number of real roots (5). In other words it crosses the x axis 5 times. So let's make one of these up and graph it
y = (x^2 - 4)(x^2 - 1)(x + 3) Study this for a minute. The leading coefficient of this polynomial is plus 1. There are no negatives in front of the x. The highest degree is x^5. Now here's the key question: on the left side where does the graph start? In Quad three right? It's coming from the lower left. That is exactly what graph C is NOT doing. So for C the graph has a leading coefficient that is less than 0. a<0
Not C.
D is not the answer either. It opens downward and looks like it is something like y = - x^4 + 3x^3 - 2x^2 + 5x - 2
Answer B:
12 + 2 - (4 × 5^2) ÷ 7 + 1
12 + 2 - (4 × 25) ÷ 7 + 1
12 + 2 - 100 ÷ 7 + 1
12+2-100/7+1
15-100/7
Equal 5/7
Rise over run 5 is rise and 7 is run