Given that Jon said,
"m-1 is always greater than 1-m"
we want to find how true the statement is;

secondly for negative values of m;

So, the statement "m-1 is always greater than 1-m" is false.
Because 1- m is greater than m-1 when m is a negative integer.
Therefore, I Disagree, because 1- m is greater than m-1 when m is a negative integer
Answer:(f/g)(x)=(1+2x)/(1-3x) where x<>0
Step-by-step explanation:
f(x)= 1/x+2= (1+2x)/x , x<>0
g(x)=1/x-3=(1-3x)/x , x<>0
=>f(x)/g(x)= (1+2x)/(1-3x) , x<>0
Answer: 
Step-by-step explanation:
Since Gloria cannot pay for each minute talked but for packages of 200 minutes at the rate of $25 each, we have to make calculations according to these conditions as follows:
Month 1:
Gloria talked on her cell phone for
. So, she had to buy 2 packages of
for
each package.
Hence:

Month 2:
Gloria talked on her cell phone for
. So, she had to buy again 2 packages of
for
each package.
Hence:

Month 3:
Gloria talked on her cell phone for
. So, she had to buy 3 packages of
for
each package.
Hence:

Then, if we take the total Gloria had to pay for the frist three months, we have:

Answer:
x > - 11/10
(I don't know if this is correct or not, if so i'm glad i helped!)
1/2 x 3/4
1 x 3 / 2 x 4
= 3/8