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HACTEHA [7]
3 years ago
7

Simplify each of the expressi 1) (5p2 – 3) + (2p2- 3p)

Mathematics
1 answer:
prohojiy [21]3 years ago
4 0

Answer:

7p^2 - 3p - 3

Step-by-step explanation:

the simplified version of the expression is 7p^2 - 3p - 3

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Help me !! With number 3! I’ll mark you brainly
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Answer:  

2 A. Exponential  Expression.

2 B. Linear.

3 A. Linear.

3 B.  Exponential Expression.

6 0
3 years ago
How many times must i ask :(
Solnce55 [7]

Step-by-step explanation:

ask for what, if you need help you

5 0
3 years ago
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Solve the equation thanks
sashaice [31]
X=-2y+3
Is your answer hope this helps
4 0
3 years ago
Solve in attachment....​
olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

\displaystyle  \int_{0} ^{1} 5x \sqrt{x} dx

use constant integration rule which yields:

\displaystyle  5\int_{0} ^{1} x \sqrt{x} dx

notice that we can rewrite √x using Law of exponent therefore we obtain:

\displaystyle  5\int_{0} ^{1} x \cdot  {x}^{1/2} dx

once again use law of exponent which yields:

\displaystyle  5\int_{0} ^{1}  {x}^{ \frac{3}{2} } dx

use exponent integration rule which yields;

\displaystyle  5 \left( \frac{{x}^{ \frac{3}{2}  + 1  } }{ \frac{3}{2}  + 1} \right)  \bigg|  _{0} ^{1}

simplify which yields:

\displaystyle  2 {x}^{2}  \sqrt{x}   \bigg|  _{0} ^{1}

recall fundamental theorem:

\displaystyle  2 (  {1}^{2}) (\sqrt{1}  ) - 2( {0}^{2} )( \sqrt{0)}

simplify:

\displaystyle  2

hence

our answer is A

8 0
2 years ago
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Find the slope of the line passing through the pairs of points and describe the line as rising, falling, horizontal or vertical.
Anna [14]

Answer:

a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

If

m > 0, then a line is rising

m < 0, then a line is falling

m = 0, then a line is horizontal

m is undefined, then a line is vertical

<h2>a.</h2>

(2, 1) and (4, 5)

m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}

<h2>b.</h2>

(-1, 0) and (3, -5)

m=\dfrac{-5-0}{3-(-1)}=\dfrac{-5}{4}=-\dfrac{5}{4}

<h2>c.</h2>

(2, 1) and (-3, 1)

m=\dfrac{1-1}{-3-2}=\dfrac{0}{-5}=0\to\text{horizontal}

<h2>d.</h2>

(-1, 2) and (-1, -5)

m=\dfrac{-5-2}{-1-(-1))}=\dfrac{-7}{0}\ \text{UNDEFINED}\to\text{vertical}

7 0
3 years ago
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