Answer + Step-by-step explanation:
<u><em>your question is about equation 4</em></u> :

Then

Then

Then

Answer:
4. 7.8
Step-by-step explanation:
Let's find the distance between (-2,-1) and (3,5):-
D=√( x_1-x_2)^2+(y_1-y_2)^2
D= √(3+2)^2+(6)^2
D= √(61)
D= 7.8
Therefore, option 4 is your answer.
Hope this answers your question!!
Remember The domain is always the left side of the relation. The range is always in the right.
Answer is C
The 400th term is 425.There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are
![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 =
425.