I need help with this

What’s -32 + (-19) + 12 with steps shown?

ad-work [718]

Answer:

-39

Step-by-step explanation:

-32-19+12

= -51+12

= -39

8 0

2 years ago

Read 2 more answers

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

2 years ago

write and equation of the line that passes through the given point and is parallel to the given line.1. (4,7), y = 5x-3

Gennadij [26K]

Answer:

y=5x+7

Step-by-step explanation:

parallel lines have the same slope, but different y intercepts

y=5x+7

5 0

3 years ago

All side lengths in quadrilateral PQRS measure 4 units. A transformation maps PQRS to P'Q'R'S'. All sides of P'Q'R'S' measure 1

VladimirAG [237]

The answer is no, the side lengths are not persevered. <span />

6 0

2 years ago

Read 2 more answers

HELP IM DOIN A MATH TEST AND IM STUCK!!!!! Tim knows the volume In bass area of a wooden chest that is in the shape of a rectang

ki77a [65]

Answer:

Height is 1 1/24 unit.

Step-by-step explanation:

Given:

volume = 5/24 unit³

base area = 1/5 unit²

Rectangular prism:

volume = length * width * height

base area = length * width

Volume = base area * height

height = volume / base area

h = 5/24 ÷ 1/5

h = 5/24 * 5/1 = 5*5 /24*1 = 25/24 = 1 1/24 unit

(hope this helps can i plz have brainlist :D hehe)

7 0

2 years ago