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bearhunter [10]
3 years ago
7

Find 5 Rational Numbers Between 1 and 2 using (a+b/2) where a=1 and b=2.

Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

Answer:

There are two ways to find the rational number between any two numbers. I will tell you an easy method to find it.

As we have to find 5 rational numbers between 1 & 2

Take 5 and add 1 to it i.e. 5+1= 6

Now take the first number and multiply and divide it by 6 i.e.

1x6/6 = 6/6

Also take the second number and multiply and divide it by 6 i.e.

2x6/6= 12/6

This is done to convert 1 & 2 into rational number i.e. in form of p/q

Now we have two numbers 6/6 and 12/6 so five rational numbers between them are

7/6, 8/6, 9/6, 10/6, 11/6

The values of these number you can check will be between 1 & 2. Actually between any two number there are infinite number of rational numbers.

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check the picture below.


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6 0
3 years ago
Which expression correctly represents "twice the sum of four and a number"?
Lesechka [4]

Answer:

2(4+x)

Step-by-step explanation:

"Twice the sum of" tells us it will be the equation times two

"the sum of four and a number" is easy, thats 4 + x

The second number is x because the number is not specified so we need a place holder, x in this case, to tell us that the number is not given.

All this put together = twice the sum of four and a number, or <u>2(4+x)</u>

7 0
4 years ago
X^3+3x^5=x5 what's the missing expression
shutvik [7]
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3 0
3 years ago
Read 2 more answers
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kozerog [31]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Who Washes? Erica and Aaron, who are siblings, have decided to use a lottery system to decide who will wash dishes every night.
Anestetic [448]

Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.

They put some red and blue power chips and draw each one.  If same colour, Aaron will wash and if not same colours Erica will wash

If the game is to be fair, then both should have equal chances of opportunity for washing.

i.e. Probability for Erica washing = Prob of Aaron washing

i.e. P(different chips) = P(same colour chips)

Say there are m red colours and n blue colours.

Both are drawing at the same time.

Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2

Probfor different colour = mC1+nC1/(m+n)C2

The two would be equal is mC2 +nC2 = m+n

This is possible if mC2 =m and nC2 = n.

Or m = 2+1 =3 and n =3

That for a fair game we must have both colours to be 3.


3 0
3 years ago
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