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ozzi
3 years ago
12

Act~abc. What is the value of x

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0
The value of it is numbers
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Drag the slider to 2 inches. How many centimeters are in 2 inches? There are centimeters in 2 inches.
choli [55]

Answer: 5


Step-by-step explanation: There are 2.5 cm per in, so its just 2.5*2


4 0
3 years ago
Read 2 more answers
A fair six sided die is rolled 1800 times, what is the theoretical probability that a 5 is rolled?
d1i1m1o1n [39]

Answer:

360 percent. 360 percent probability i think

4 0
4 years ago
When we toss a coin, there are two possible outcomes: a head or a tail. Suppose that we toss a coin 100 times. Estimate the appr
marin [14]

Answer:

96.42% probability that the number of tails is between 40 and 60.

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

100 tosses, so n = 100

Two outcomes, both equally as likely. So p = \frac{1}{2} = 0.5

So

E(X) = np = 100*0.5 = 50

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.5*0.5} = 5

Estimate the approximate probability that the number of tails is between 40 and 60.

Using continuity correction.

P(40 - 0.5 \leq X \leq 60 + 0.5) = P(39.5 \leq X \leq 60.5)

This is the pvalue of Z when X = 60.5 subtracted by the pvalue of Z when X = 39.5. So

X = 60.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{60.5 - 50}{5}

Z = 2.1

Z = 2.1 has a pvalue of 0.9821

X = 39.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.5 - 50}{5}

Z = -2.1

Z = -2.1 has a pvalue of 0.0179

0.9821 - 0.0179 = 0.9642

96.42% probability that the number of tails is between 40 and 60.

8 0
3 years ago
An art gallery displays a large painting in the center of a wall that is 24 feet ( ft wide. The painting is 10ft wide. Which of
san4es73 [151]

the complete question in the attached figure

step 1

Find the distance of the center of the wall from the left end of the wall

distance=(1/2)*24--------> 12 ft

so

If x is the distance from a painting edge to its corresponding end of the wall, then

|x-12| is the distance from the painting edge to the center of the wall

and

If the painting is centered, then 2|x-12| represents the width of the painting

Since the painting is 10 ft wide,

we have 2|x-12|=10

therefore

the answer is the option B

2|x-12|=10

8 0
3 years ago
Please help with math
OleMash [197]

Answer:

i think linear

Step-by-step explanation:

let me know if this is wrong

7 0
3 years ago
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