Remember you can do anything to an eqautoin as long as you do oit to both sides
-5x=15
try to get 1x by itself
remember
(ax)/a=x when a=a
so
-5x=15
get x
divide both sides by -5
remember to flip sign
(-5x)/(-5)=15/(-5)
x=-3
answer is first one
x=-3
Any value as long as P = Q
For the equation to have infinitely many solutions, we require both sides of the equation to have exactly the same terms.
34 times 50 plus 34 divided by 60 equals 28.9
Round all dollar values to the nearest cent, and consider the trade-in to be a reduction in the amount paid
b.
$38,821
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
