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2 years ago

10

HELP: Subsets Attached is the photo reference

1 answer:

AlexFokin [52]2 years ago

3 0

Answer:

(B ∩ A) U C = {q, r, z, h, p, y}

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What is m-a = n+p, for a

sergeinik [125]

Answer:

A=m-n-p

Step-by-step explanation:

So solve for a, we have to isolate it on one side, so -a=n+p-m. So a=m-n-p

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2 years ago

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The difference of Ellen’s age and her sister Mary’s age is 4 years. Ellen is 5 years less than twice Mary’s age.

Paha777 [63]

Answer:

I believe the answer is 9 years old or 8 years old.

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2 years ago

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Please help! Will mark brainless

KengaRu [80]

Here’s what you can do to make this very simple. Consider that the “missing” space between the rectangles isn’t there. Then, find the area:

10 x 9 = 90 mm

Now, find the area of the “missing” part.

5 x 2 = 10 mm

Finally, you deduct the missing part from the complete rectangle!

90 - 10 = 80 mm

The area of this whole thing is 80 mm!

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2 years ago

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Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

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2 years ago

Pine Bluff Middle School is having its annual Spring Fling dance, which willcost $400. The student treasurer reported that the d

Anit [1.1K]

This year's dance needs 82 tickets.

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3 years ago