Answer:
13.63%
Step-by-step explanation:
In box 1, there are a total of:
3 + 2 + 4 + 2 = 11 objects, therefore the probability of drawing a comb network is:
11/3
because there are in total 3 network comb
Now, in box 2, there are only 2 objects, one of each, therefore the probability is
1/2
The final probability would be:
11/3 * 1/2 = 0.1363
That is to say of a 13.63%
Answer:
35
Step-by-step explanation:
55 + x = 90
x = 90 - 55
x = 35
<em><u>The required average on next two tests are:</u></em>
![t\geq \frac{450-p}{2}](https://tex.z-dn.net/?f=t%5Cgeq%20%5Cfrac%7B450-p%7D%7B2%7D)
<em><u>Solution:</u></em>
An A grade will be given to students having at least 450 total test points
Let p represent her present test point total, and t represent the necessary average on the next two tests
There are two more tests to take before the semester is over
Therefore,
![p+2t\geq 450](https://tex.z-dn.net/?f=p%2B2t%5Cgeq%20450)
A grade is given to students having at least 450 total test points
"at least" means greater than or equal to
So we have used greater than or equal to symbol
Solve the inequality for "t"
![p+2t\geq 450\\\\Subtract\ p\ from\ both\ sides\\\\2t\geq 450-p\\\\Divide\ both\ sides\ by\ 2\\\\t\geq \frac{450-p}{2}](https://tex.z-dn.net/?f=p%2B2t%5Cgeq%20450%5C%5C%5C%5CSubtract%5C%20p%5C%20from%5C%20both%5C%20sides%5C%5C%5C%5C2t%5Cgeq%20450-p%5C%5C%5C%5CDivide%5C%20both%5C%20sides%5C%20by%5C%202%5C%5C%5C%5Ct%5Cgeq%20%5Cfrac%7B450-p%7D%7B2%7D)
Thus the required average on next two tests are:
![t\geq \frac{450-p}{2}](https://tex.z-dn.net/?f=t%5Cgeq%20%5Cfrac%7B450-p%7D%7B2%7D)