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3 years ago

8

The hyperbola with center at (0, 0) opening horizontally, with a = 2, b = 5.

1 answer:

Finger [1]3 years ago

8 0

I dont know if this is what you are looking for but i think this is the answer of the question you are looking for which is the general equation of a horizontal hyperbola:
<span>(x-h)²/a² - (y-k)²/b² = 1 </span>
<span>with </span>
<span>center (h,k)
</span>What you need to do is replace the data and do the calculations

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20 points! Write an exponential function in the form y=ab^x that goes through points (0, 8) and (2, 200)

alexandr402 [8]

Answer:

$y=8(5)^x$

Step-by-step explanation:

We want an exponential function that goes through the two points (0, 8) and (2, 200).

Since a point is (0, 8), this means that y = 8 when x = 0. Therefore:

$8=a(b)^0$

Simplify:

$a=8$

So we now have:

$y = 8( b )^x$

Likewise, the point (2, 200) tells us that y = 200 when x = 2. Therefore:

$200=8(b)^2$

Solve for b. Dividing both sides by 8 yields:

$b^2=25$

Thus:

$b=5$

Hence, our exponential function is:

$y=8(5)^x$

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<em>Because you add the 2x and the x and you get 3x then there is a 90 degree angles so you add that and =180</em>

<em>Once you put it in the equation you can subtract 90 from 180 and you get 90 which you then divided by 3x and x equals 30</em>

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