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2 years ago

Which value of h make the equation true? 2.3 + h = 7.8

Mathematics

1 answer:

Nat2105 [25]2 years ago

3 0

Answer:

h = 5.5

Step-by-step explanation:

2.3 + h = 7.8

-2.3 -2.3

h = 5. 5

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The figures are similar. Find x.

DaniilM [7]

Answer:

My own answer to your question is x=10

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2 years ago

If a circle has a radius of 5 meters, what<br> is the diameter?

Rom4ik [11]

Answer:

10m

Step-by-step explanation:

Radius is half the diameter.

So, 5x2 = 10

Answer: 10m

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2 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

Can someone help me with this problem ?

Alecsey [184]

The answer is 83. 83+5=88. just subtract it.

5 0

2 years ago

Read 2 more answers

3 - x/2 = 6 (Solve each equation) Check your answer

Yanka [14]

Answer to question
3-x/2=6
Subtract 3 from both sides
-x/2=3
Multiply 3 by -2
Final Answer: x=-6

Work check
3-x/2=6
Substitute -6 for x since you solved for x in the last equation
3-(-6)/2
Convert 3-(-6/2) to 3+6/2
3+6/2
Divide 6 by 2
3+3
Add
Final Answer: 6 (This 6 is the same 6 we used to solve for x in the first equation).

6 0

3 years ago