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Vladimir79 [104]
3 years ago
5

Solve −2x2 +3x − 9 = 0. (2 points)

Mathematics
2 answers:
NISA [10]3 years ago
6 0

Answer:

Option A) x equals quantity of 3 plus or minus 3i square root of 7 all over 4.

Step-by-step explanation:

We are given the quadratic equation:

-2x^2 +3x - 9 = 0

To find the solution to this quadratic equation, we use the quadratic formula:

ax^2 + bx + c = 0\\\\x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\\text{where a is the coefficient of } x^2\text{, b is the coefficient of x and c is the constnt term of the eqution.}

Putting the value of a, b and c in the quadratic formula:

a = -2\\b = 3\\c = -9\\\\x = \displaystyle\frac{-3 \pm \sqrt{3^2 - 4(-2)(-9)}}{2(-2)}\\\\x = \frac{-3 \pm \sqrt{-63} }{-4}\\\\x = \frac{-3 \pm 3i\sqrt7}{-4}\\\\x = \frac{3 \mp3i\sqrt7}{4}

Hence, the correct option is option A) x equals quantity of 3 plus or minus 3i square root of 7 all over 4.

nadya68 [22]3 years ago
3 0

Answer:

Option A

Step-by-step explanation:

We have to find the solution of -2x^{2}+3x-9=0

By quadratic formula

x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

=\frac{-3\pm \sqrt{(3)^{2}-4(-2)(-9)}}{2(-2)}

=\frac{-3\pm \sqrt{9-72}}{-4}

=\frac{3\mp \sqrt{-63}}{4}

\frac{3\mp 3\sqrt{-7}}{4}=[\frac{3\mp 3i\sqrt{7}}{4}]

Option A is the answer.

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I need an equation that has variables on both sides were x = 17
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9 + 3x = 5x - 25

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According to Descartes rule what is a possible number of positive and negative roots
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sepalacola

Step-by-step explanation:

3 0
2 years ago
PLEEZZ
jonny [76]

4 < 4(6y - 12) - 2y       |use distributive property

4 < (4)(6y) + (4)(-12) - 2y

4 < 24y - 48 - 2y       |add 48 to both sides

52 < 26y      |divide both sides by 26

2 < y → y > 2

---------------------------------------------------------

4x + 3 < 3x + 6      |subtract 3 from both sides

4x < 3x + 3       |subtract 3x from both sides

x < 3

------------------------------------------------------------

-5r + 6 ≤ -5(r + 2)        |use distributive property

-5r + 6 ≤ (-5)(r) + (-5)(2)

-5r + 6 ≤ -5r - 10         |add 5r to both sides

6 ≤ -10     FALSE

No solution

-------------------------------------------------------------

-2(6 + s) ≥ -15 - 2s        |use distributive property

(-2)(6) + (-2)(s) ≥ -15 - 2s

-12 - 2s ≥ -15 - 2s        |add 2s to both sides

-12 ≥ -15     TRUE

All real numbers

-------------------------------------------------------------

3s + 6 ≤ -5(s + 2)        |use distributive property

3s + 6 ≤ (-5)(s) + (-5)(2)

3s + 6 ≤ -5s - 10         |subtract 6 from both sides

3s ≤ -5s - 16        |add 5s to both sides

8s ≤ -16         |divide both sides by 8

s ≤ -2

--------------------------------------------------------------

4/3 s - 3 ?

4 0
2 years ago
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