Domain: -∞<x<∞
Range: -∞<x<∞
X-Intercept: x=0
Y-Intercept: y=0
Increasing on the interval of 0<x<∞
<span>Decreasing on the interval of -∞<x<0
</span>When A=0, the graph equals y=0
- When A is greater than 1, it makes the graph skinnier than <span>f(x)=|x|
- When A is less than 1 but greater than 0, it makes the graph fatter than </span><span>f(x)=|x|
- When A turns negative, it flips the graph upside down.
-When B is greater than 0, it translates the graph to the right
- When B is less than 0, it translates the graph to the left
When C is greater than 0, the graph moves upwards
When C is less than 0, the graph moves downwards</span>
Answer:
D. $31,337.27
Step-by-step explanation:
We have that the initial amount of the loan is $5500.
Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.
The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.
Also, it is given that the loan was compounded annually.
We have the formula as,
i.e. ![PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7B-t%5Ctimes%20n%7D%5D%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D)
Substituting the values, we get,
i.e. ![PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7B0.075%7D%7B12%7D%29%5E%7B-10%5Ctimes%2012%7D%5D%7D%7B%5Cfrac%7B0.075%7D%7B12%7D%7D)
i.e. ![22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B0.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-0.4735]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-0.4735%5D%7D%7B0.00625%7D)
i.e. 
i.e. 
i.e. 
i.e. 
Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2
Hence, the total cost close to the answer is $31,337.27
Answer:
3x - 6
Step-by-step explanation:
To evaluate f(2x) and f(x + 2) substitute x = 2x and x = x + 2 into f(x)
f(2x) = 3(2x) - 2 = 6x - 2
f(x + 2) = 3(x + 2) - 2 = 3x + 6 - 2 = 3x + 4
Thus
f(2x) - f(x + 2)
= 6x - 2 - (3x + 4)
= 6x - 2 - 3x - 4
= 3x - 6
Answer: 31 mint plants
Step-by-step explanation:
We will have mint plants over total plants:
29/29+29 = 29/58 = 1/2
Now, we will multiply 62 by 1/2 to guess how many mint plants will be stocked.
62* 1/2 = 31
We should expect about 31 plants of the total plants to be mint plants.
