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AnnZ [28]
3 years ago
15

Please help and add explanation:)

Mathematics
1 answer:
Anni [7]3 years ago
8 0

Answer:

NO

Step-by-step explanation:

The above image shows two triangles. if we look at the top triangle, we notice it's two sides are equal (16 and 16). We therefore have an isosceles right triangle.

looking the second triangle, we notice that one side is 39, the other 40. Since these are the two sides joined at the point of intersection for the two images, and since 39 does not equal 40, the second triangle cannot be an isosceles right triangle. We conclude that the two triangles are not similar.

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Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Compute the proba
sergejj [24]

Answer:

P [ 55 ≤ X ≤ 70 ] = 23.55 %

Step-by-step explanation:

We know:

μ₀ = mean of population              σ  = standard deviation  

We begin for calculating the probability of X ≤ 55 so

Step 1:

μ₀  = 50              σ = 7

×₁    =   ( μ - μ₀ ) ÷ σ   ⇒  ×₁  = (55-50) ÷ 7     ⇒  ×₁  = 5 ÷ 7    ×₁ = 0.7143

We look z table and we have to interpolate

value (closest smaller Than    ×₁   0.71   and closest bigger than ×₁   0.72

The associated area for these point are:   0.7611 and 0.7642

Taking diferences and by rule of three

0.01             ⇒  0.0031

0.0042        ⇒      Δ          Δ = 0.0013     and  Area for ×₁  = 0.7624

That is the probability of  X ≤ 55

Now we have to find the probability of X ≤ 70

We procede as in step 1

μ₀  = 50             σ = 7

×₂    =   ( μ - μ₀ ) ÷ σ   ⇒  ×₂  = (70-50) ÷ 7     ⇒  ×₂  = 20 ÷ 7    ×₂ = 2.8571

We look z table and we have to interpolate

for 2.85    ⇒ 0.9978 (area)              2.8571 - 2.85  = 0.007

for 2.86    ⇒ 0.9979 (area)

Therefore by rule of three we have

0.01      ⇒    0.0001

0.007   ⇒        Δ                       Δ = 0.00007

And area for      ×₂ = 2.8571      is  equal to 0.99787   and the probability of

X ≤ 0.99787   or    99.79

Now if we look the annex drawing (the area we are looking for is enclose for the values x₁   and ×₂  (pink area) and is the diference between these two areas

So   P [ 55 ≤ X ≤ 70 ]  is 99.79 % - 76.24 %  = 23.55

 

4 0
3 years ago
Mathematics achievement test scores for 300 students were found to have a mean and a variance equal to 600 and 3600, respectivel
Zina [86]

Answer:

(a) Approximately 205 students scored between 540 and 660.

(b) Approximately 287 students scored between 480 and 720.

Step-by-step explanation:

A mound-shaped distribution is a normal distribution since the shape of a normal curve is mound-shaped.

Let <em>X</em> = test score of a student.

It is provided that X\sim N(\mu = 600, \sigma^{2} = 3600).

(a)

The probability of scores between 540 and 660 as follows:

P(540\leq X\leq 660)=P(\frac{540-600}{\sqrt{3600} }\leq \frac{X-600}{\sqrt{3600} }\leq \frac{660-600}{\sqrt{3600} })\\=P(-1 \leq Z\leq 1)\\= P(Z\leq 1)-P(Z\leq -1)\\=0.8413-0.1587\\=0.6826

Use the standard normal table for the probabilities.

The number of students who scored between 540 and 660 is:

300 × 0.6826 = 204.78 ≈ 205

Thus, approximately 205 students scored between 540 and 660.

(b)

The probability of scores between 480 and 720 as follows:

P(480\leq X\leq 720)=P(\frac{480-600}{\sqrt{3600} }\leq \frac{X-600}{\sqrt{3600} }\leq \frac{720-600}{\sqrt{3600} })\\=P(-2 \leq Z\leq 2)\\= P(Z\leq 2)-P(Z\leq -2)\\=0.9772-0.0228\\=0.9544

Use the standard normal table for the probabilities.

The number of students who scored between 480 and 720 is:

300 × 0.9544 = 286.32 ≈ 287

Thus, approximately 287 students scored between 480 and 720.

3 0
3 years ago
Complete ☻☺<br><br> z^2 + 9z – 90 = (z – 6)(z +■)<br><br> A.) -15<br> B.) 15<br> C.) 90<br> D.) -9
irina [24]
The answer is B) 15

I hope this helps
4 0
3 years ago
Read 2 more answers
What is the exponential notation for 262,144
7nadin3 [17]

since there is always a decimal at the end of every value so :

           = 262144.0 

        you move the decimal backwards if there is no decimal between the value. you place the decimal after the 1st digit, you will also count the digits you have passed : 

         = 2.62144 X 10^5 

you passed 5 values so you put 5 in exponent form.


7 0
3 years ago
Read 2 more answers
Twelve million seven hundred three write in standard form
pickupchik [31]

Answer:

12,000,703

Step-by-step explanation:

Standard form will always be in number form.

5 0
4 years ago
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