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3 years ago

HELP ME ANSWER IT PLZ ASAP 6(6x−1)=5(5x+4)−2x

Mathematics

2 answers:

mote1985 [20]3 years ago

8 0

Answer:

Step-by-step explanation:

Alexxx [7]3 years ago

8 0

Answer:

X=2

Step-by-step explanation:

36x - 6= 23x + 20 - 2x

36x - 6= 23x + 20

36x - 23x= 20 + 6

13x= 26

x= 2

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if 6th term of an ap is -10 and 10 th term is -26 then find thr 15 term plzzzzzzzzzzzzzzzzzzzzzzz answer i will give whatever y

Rudik [331]

Answer:

-46

Step-by-step explanation:

We need to find the common difference of this arithmetic sequence:

$\frac{-26-(-10)}{10-6} =\frac{-16}{4} =-4$

So, the common difference d = -4. We can now write the equation:

$a_n=a_1+d(n-1)$

$a_{15}=a_6+d(15-6)=-10-4(9)=-10-36=-46$

So, the 15th term is -46.

Hope this helps!

5 0

2 years ago

Read 2 more answers

Please help if you can pic attatched

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

$CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

Subtract row 3 from row 1:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]$

Subtract row 3 from 7 times row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]$

Divide row 3 by 17:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 2 of row 3 from row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 6 of row 2 from row 1:

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

$C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]$

$C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]$

3 0

3 years ago

The table below shows an input/output relationship. Find the Starting Value/y-intercept.

MAVERICK [17]

Answer:

Input 0 and Output -6

Step-by-step explanation:

The reason why is that we know that -4 has a output of -18 which -3 has a output of -15 meaning each time x increases by 1 the output increases by 3. 1:3 ratio basically so since we know this the starting value should be

y=0+3x

6 0

3 years ago

Kali earns $8 per hour. She worked x hours on both Monday and Tuesday. She also worked 5 hours on Thursday. The expression that

quester [9]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Mhanifa please help im almost done! I will mark brainliest :)

slava [35]