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Viktor [21]
3 years ago
6

Determine the measure of an angle whose measure is 17 times that of its complement.

Mathematics
2 answers:
IrinaK [193]3 years ago
6 0

Answer:

85⁰

Step-by-step explanation:

Angle = x

Complement = 90 - x

Given :

x = 17 (90 - x)

x = 1530 - 17x

18x = 1530

x = 1530/18 = 85⁰

Iteru [2.4K]3 years ago
4 0
Complement angles are angles which when added, the sum is equal to 90 degrees. In this case, we let angle one as x while angle 2 is represented by 17x. The equation then is equal to x + 17x = 90 ; 18x = 90. x from the equation is equal to 5. Hence teh angles are 5 degrees and 85 degrees
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<span>Each team in the softball league plays each of the other teams exactly once. For every game, there is 2 team playing. The order is not important because  A vs B is same as B vs A
So you just need to makes a combination of 2 that have a result of 21. If there is t number of teams, the number of matches would be:
tC2 = t!/2!(t-2)! = 21
</span>t! / (t-2)! = 21 *2
(t)(t-1)= 42
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3 years ago
What is √7 rounded to the nearest hundredth?
Rama09 [41]

Answer:

2.64

Step-by-step explanation:

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3 years ago
A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row. All the lights start out off. The first
Gnom [1K]

<u>Solution-</u>

A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row.

As all the lights start out off, in the first pass all bulbs will be turned on.

In the second pass all the multiples of 2 will be off and rest will be turned on.

In the third pass all the multiples of 3 will be off, but the common multiple of 2 and 3 will be on along with the rest. i.e all the multiples of 6 will be turned on along with the rest.

In the fourth pass 4th light bulb will be turned on and so does all the multiples of 4.

But, in the sixth pass the 6th light bulb will be turned off as it was on after the third pass.

This pattern can observed that when a number has odd number of factors then only it can stay on till the last pass.

1 = 1

2 = 1, 2

3 = 1, 3

<u>4 = 1, 2, 4</u>

5 = 1, 5

6 = 1, 2, 3, 6

7 = 1, 7

8 = 1, 2, 4, 8

9 = 1, 3, 9

10 = 1, 2, 5, 10

11 = 1, 11

12 = 1, 2, 3, 4, 6, 12

13 = 1, 13

14 = 1, 2, 7, 14

15 = 1, 3, 5, 15

16 = 1, 2, 4, 8, 16

so on.....

The numbers who have odd number of factors are the perfect squares.

So calculating the number of perfect squares upto 1800 will give the number of light bulbs that will stay on.

As,  \sqrt{1800} =42.42  , so 42 perfect squared numbers are there which are less than 1800.

∴ 42 light bulbs will end up in the on position. And there position is given in the attached table.

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