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3 years ago

Helpppp which is true

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

6 0

Answer:

The answers is

x=−1

Step-by-step explanation:

Can you give me Brainleist please :)

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1. Henri cut a rope into two pieces with lengths having a ratio of 5 to 2. The shorter piece is

ruslelena [56]

The length of the shorter rope is 20 cm.

<h3>How to find the original length of the rope using ratio?</h3>

He cut a rope into two pieces with lengths having a ratio of 5 to 2.

The shorter piece is 70 cm long.

The length of the original rope can be calculated as follows:

The ratio of the length of the rope is as follows;

5 : 2

let

x = length of the original rope

Therefore,

length of shorter piece = 2 / 7 × 70

length of shorter piece = 140 / 7

length of shorter piece = 20 cm

Therefore, the length of the shorter rope is 20 cm.

learn more on ratio here: brainly.com/question/15418103

#SPJ1

8 0

2 years ago

The product of two consecutive odd integers is 63. If x is the smallest of the integers, write an equation in terms of x that de

kodGreya [7K]

Answer:

x*(x+2)= 63 7 and 9

Step-by-step explanation:

7 0

3 years ago

Point A(-2, -2) and B(3, -2) are dilated with the center of dilation at C(0, 0) and k=2.

frez [133]

9514 1404 393

Answer:

A'(-4, -4), B'(6, -4), parallel

Step-by-step explanation:

The dilation factor multiplies each of the coordinate values. The line that was y=-2 becomes the line y=-4, a parallel horizontal line.

6 0

3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago

10. Joseph and Tabitha were hiking and had a choice between two trails. One was

Nataly [62]

Answer:

10+5=15 sow longer trail is 15

3 0

3 years ago