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denpristay [2]
3 years ago
14

For the right triangle shown, use the trig functions to find the value of x. Round your answer to the nearest tenth.

Mathematics
2 answers:
jeka57 [31]3 years ago
7 0

Answer:

\boxed{\boxed {\sf 3. \ 9.4}}

Step-by-step explanation:

First, recall the three basic right triangle trigonometry ratios.

  • sin(θ)=opposite/hypotenuse
  • cos(θ)= adjacent/hypotenuse
  • tan(θ)= opposite/adjacent

Theta (θ) represents the angle. The angle (other than the right angle) is 70 degrees.

We are also given 2 sides: 10 and x.

  • 10 is the <u>hypotenuse</u>, because it is opposite the right angle.
  • x is <u>opposite </u>the 70 degree angle.

Since we have the opposite and hypotenuse, we must use sine.

sin (\Theta)= \frac{opposite}{hypotenuse}}

The angle is 70 degrees, the opposite is x, and the hypotenuse is 10.

sin(70)=\frac{x}{10}

We are solving for x. We must isolate x on one side of the equation.

Currently, x is being divided by 10. To "undo" the division, we must perform the inverse operation, which is multiplication. Multiply both sides of the equation by 10.

10*sin(70)=\frac{x}{10}*10

10*sin(70)=x

10*0.939692621=x

9.39692621=x

Round to the nearest tenth. The 9 in the hundredth place tells us to round the 3 up to a 4.

9.4 \approx x

x is about <u>9.4</u>

Alecsey [184]3 years ago
3 0

Answer:

<h3>First, recall the three basic right triangle trigonometry ratios.</h3>

<h3>sin(θ)=opposite/hypotenuse</h3><h3>cos(θ)= adjacent/hypotenuse</h3><h3>tan(θ)= opposite/adjacent</h3><h3>Theta (θ) represents the angle. The angle (other than the right angle) is 70 degrees.</h3>

<h3>We are also given 2 sides: 10 and x.</h3>

<h3>10 is the hypotenuse, because it is opposite the right angle.</h3><h3>x is opposite the 70 degree angle.</h3><h3>Since we have the opposite and hypotenuse, we must use sine.</h3>

<h3>sin (\Theta)= \frac{opposite}{hypotenuse}}</h3>

<h3>The angle is 70 degrees, the opposite is x, and the hypotenuse is 10.</h3>

<h3>sin(70)=\frac{x}{10}sin(70)= </h3><h3>10</h3><h3>x</h3>

<h3>We are solving for x. We must isolate x on one side of the equation.</h3>

<h3>Currently, x is being divided by 10. To "undo" the division, we must perform the inverse operation, which is multiplication. Multiply both sides of the equation by 10.</h3>

<h3>10*sin(70)=\frac{x}{10}*1010∗sin(70)= </h3><h3>10</h3><h3>x</h3>

<h3> ∗10</h3>

<h3>10*sin(70)=x10∗sin(70)=x</h3>

<h3>10*0.939692621=x10∗0.939692621=x</h3>

<h3>9.39692621=x9.39692621=x</h3>

<h3>Round to the nearest tenth. The 9 in the hundredth place tells us to round the 3 up to a 4.</h3>

<h3>9.4 \approx x9.4≈x</h3>

<h3>x is about 9.4</h3>
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