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erica [24]
3 years ago
9

If the basket had a total of 44 oranges, how many apples would the basket have? Draw a tape diagram to represent your answer

Mathematics
1 answer:
REY [17]3 years ago
4 0

Answer: This makes no sense whatsoever. How would we know how many apples their were simply from the fact there are 44 oranges???  Was there more info we missed???

Step-by-step explanation:

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Given: ⅓ (18x + 27) = 81 Prove: x = 12
sasho [114]

Answer:

Firstly, rewrite the equation:

⅓ (18 + 27) = 81

Substitute x for the given number of it's supposed equivalent.

In this case x = 12.

⅓ (18(12) + 27) = 81

Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.

(18 x 12) + 27 = 243

Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .

⅓ (243) = 81

When you multiple these number they are equivalent to 81.

81 = 81

Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.

4 0
3 years ago
At wild thing zoo, you can rent a motorized cart to tour grounds for a $3 initial charge and $7 per hour. at safari zoo, you can
makvit [3.9K]
When setting up the equation you have the initial fee and the hourly fee. The hourly fee is what must be multiplied by the number of hours which is our unknown

6 0
3 years ago
Last year, Shen opened an investment account with $7800. At the end of the year, the amount in the account had decreased by 22.5
maks197457 [2]

Answer:

The decrease was $1755.

At the end of the year, he had $6045 in his account.

Step-by-step explanation:

Start with $7800.

Decrease of 22.5% of $7800.

22.5% of $7800 =

= $1755

The decrease was $1755.

$7800 - $1755 = $6045

At the end of the year, he had $6045 in his account.

4 0
3 years ago
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.
lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

H_0: \mu \leq 220000

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

H_1: \mu > 220000.

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem:

\overline{x} = 226450, \mu = 220000, s = 11500, n = 23

Then, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}

t = 2.69

We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0
3 years ago
Max rented a motorbike at $465 for 5 days. If he rents the same motorbike for a week, he has to pay a total rent of $625.
garri49 [273]
The answer is simple you divide $465 from 5 then multiply
6 0
3 years ago
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