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3 years ago

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20so%20really%20soon%21%20I%20need%20to%20show%20my%20work" id="TexFormula1" title="I need help can someone help? I’m really stuck and it’s so really soon! I need to show my work" alt="I need help can someone help? I’m really stuck and it’s so really soon! I need to show my work" align="absmiddle" class="latex-formula">

1 answer:

Dovator [93]3 years ago

3 0

The pictures are blurry I can’t see anything

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Two number cubes are rolled .what is the probability that the sum of the numbers on the cubes is 12 ?? The Answer is fraction

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4 years ago

On a particular day, 112 of 280 passengers on a particular DTW-LAX flight used the e-ticket check-in kiosk to obtain boarding pa

Sonja [21]

Answer:

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

Step-by-step explanation:

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Population of 280, which means that $N = 280$

112 use e-ticket check-in kiosk, which means that $k = 112$

Sample of eight passengers means that $n = 8$

Find the approximate hypergeometric probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

This is P(X = 4). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 4) = h(4,280,8,112) = \frac{C_{112,4}*C_{168,4}}{C_{280,4}} = 0.2348$

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

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3 years ago

The population of a large city is gradually moving to outlying metropolitan areas with the decline predicted by the functional e

Andrews [41]

I’m not sure m8 but u gave me some points thanks man

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