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3 years ago

5

A first play of football game resulted in a loss of 12.5 yards. Then a penalty resulted in another loss of 5 yards. What is the

total loss or gain?

1 answer:

lions [1.4K]3 years ago

8 0

The total loss is 17.5 yards.

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Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet,

MatroZZZ [7]

The two quadrilaterals are given similar .

In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .

The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC

We can form a proportion with the proportional sides:

$\frac{16}{x} =\frac{12}{18}$

To solve for x we cross multiply

12x=(16)(18)

12x=288

Dividing both sides by 12 we get

x=24.

The second longest side of quadrilateral EFGH is 24 ft.

6 0

4 years ago

Write an expression showing 5 less than the number K

BigorU [14]

Answer:

k-5

Step-by-step explanation:

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3 years ago

At the movies, you order 3 boxes of popcorn and a bottle of water. The cost of the bottle of water Is $1.75. Your total is $9.25

Phoenix [80]

If popcorn is p and water is w the equation can be written as

3p + w = 9.25

because there was 3 boxes of popcorn and one water (hence the coefficients) and the total is 9.25

then plug in 1.75 for w the price of water:

3p+ 1.75 = 9.25

you can move stuff around algebraically now (subtract 1.75 on both sides and divide by three on both aides) to get the cost of one box of popcorn (p).

The answer is 2.50

8 0

3 years ago

The length of a rectangle is six times it’s width.If the area of the rectangle is 486 inches squared find its perimeter.

defon

<span>T
Width is 8 and the length is 48! Then add all sides, 8+8+48+48=112.<span>
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6 0

4 years ago

Read 2 more answers

Simplify the expression.<br> c^-6 d^4/c^-16 d^14

pochemuha

Answer:

$\red{\frac{ {c}^{10}}{{d}^{10} } }$

Step-by-step explanation:

$\huge \: \frac{ {c}^{ - 6} {d}^{4}}{ {c}^{ - 16} {d}^{14} } \\ \\ = \huge \: \frac{ {c}^{16 - 6}}{{d}^{14 - 4} } \\ \\ = \huge \: \red{\frac{ {c}^{10}}{{d}^{10} } }$

6 0

2 years ago